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Expand your Russian vocabulary with this handy app. You can use this app to find any Russian word based on the last letter. Choose the letter that you want the word to end with and then how many letters in the Russian word and you can see all the Russian words that fit that criteria.
So if you select letter as A with number of letters as 10, you will get words like: аборигенка, аванкамера and 1,800 other words that end with A and have 10 letters.
The first column is the word, the second column is whether it’s singular or plural and third column is the gender.
Separately, we have other resources for finding Russian anagrams, Russian words that end with, Russian words that start with, Russian words that contain which letters (either together or apart) and lots of Russian worksheet creators.
I have a quite big string. In that big string, I want to get all UNIQUE words starts with @@ and ends with @@. Between @@ could be text, number or alphanumeric or anything.
Once I get all the UNIQUE words starting @@ and ends with @@, I want to replace each word with a value which matches a key in a different array.
Looking for the solution in C#.
asked Jul 30, 2013 at 7:00
1
Try this regex:
@@bS+?b@@
Sample Code:
List<string> lst = new List<string>();
MatchCollection mcol = Regex.Matches(sampleString,@"@@bS+?b@@");
foreach(Match m in mcol)
{
lst.Add(m.Tostring());
}
Here lst
contains matched value(s), compare each value and replace it as per you criteria.
Sample live demo
answered Jul 30, 2013 at 7:10
NeverHopelessNeverHopeless
11k4 gold badges34 silver badges56 bronze badges
7
Try following code (use Regex.Replace Method):
string s = @"@@Welcome@@ to @@reg-ex@@ @@world@@.";
Dictionary<string, string> sub = new Dictionary<string,string>{
{ "@@reg-ex@@", "regular expression" },
{ "@@world@@", "hell" },
};
Regex re = new Regex(@"@@.*?@@");
Console.WriteLine(re.Replace(s, x => {
string new_x;
return sub.TryGetValue(x.ToString(), out new_x) ? new_x : x.ToString();
}));
prints:
@@Welcome@@ to regular expression hell.
answered Jul 30, 2013 at 7:25
falsetrufalsetru
352k62 gold badges716 silver badges630 bronze badges
1
Example using Regex and Linq
string text = "@@bb@@@@cc@@@@sahasjah@@@@bb@@";
var matches = Regex.Matches(text, @"@@[^@]*@@");
var uniques = matches.Cast<Match>().Select(match => match.Value).ToList().Distinct();
answered Jul 30, 2013 at 7:22
2
Try this one mate…..
string yourString = ""; // Load your string
string[] splits = Regex.Split(yourString, "[ nt]"); //Split the long string by spaces, t and n
foreach (string str in splits)
{
if(Regex.IsMatch(str, "^^@@.*?@@$$")) // Find words starting and ending with @@
{
// You may replace either splits values or build a new string according your specification
}
}
answered Jul 30, 2013 at 7:20
You could maybe do the following
Regex regex = new Regex("@@(.*)@@");
Or, if you dont want Regex use the following (easier to understand i think)
var splittedString = yourString.Split(new string[] { "xx" }, StringSplitOptions.None);
answered Jul 30, 2013 at 7:07
BudBrotBudBrot
1,2792 gold badges24 silver badges44 bronze badges
1
I would not use regexp for that. This is faster :
//Pseudo code
string[] parts = yourLongString.split("@@");
for(i=0;i<parts.length;i++){
if(parts[i].indexOf(' ')<0){
// there is no space, it is a keyword
parts[i]=yourDictionary[parts[i]];
}
}
yourFinalText=parts.join(' ');
answered Jul 30, 2013 at 7:39
bokanbokan
3,5692 gold badges23 silver badges36 bronze badges
2