Word problems about power

Below are some carefully selected power word problems to help you understand the concept of power in physics.

Problem # 1:

How much power is required to do 200 joules
of work in 4 seconds?What if you do the same work in 2 seconds? Did you
notice anything? Say what you noticed. 

Solution:

Power =  

work done
/
time interval

Power = 50 Watts or 50 joules per second

What if the same work is done in 2 seconds?

Power = 100 Watts or 100 joules per second

I noticed that more power is required to do the same work in less time.

Interesting power word problems

Problem # 2:

Which person is more powerful?

It takes John 2 seconds to lift a 100-kg barbell a distance of 20 centimeters.

It takes Peter 3 seconds to lift a 200-kg barbell a distance of 15 centimeters.

Solution:

First, convert 20 centimeters and 15 centimeters to meters.

20 centimeters = 0.20 meter and 15 centimeters = 0.15 meter.

Find the force that is required to lift 100 kg and 150 against gravity.

F = 100 × 10 = 1000 Newtons

F = 200 × 10 = 2000 Newtons

Power =  

work done
/
time interval

Power =  

F × d
/
time interval

John’s power =  

1000 × 0.2
/
2

John’s power =  

1000
/
2

× 0.2

Power = 500 × 0.2

Power = 100 Watts or 100 joules per second

John’s power =  

2000 × 0.15
/
3

Power = 100 Watts or 100 joules per second

John and Peter have the same power.

Problem # 3:

The power of a machine is 4 kilowatts. How
much work can this machine do in 1 second ? Answer should be in Newtons/
4 meters. Don’t use the formula to solve this problem!

If you still cannot do it without using the formula, click here to see the solution.

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Power is the amount of work done (energy supplied) per unit time. In physics, power is the amount of energy transferred or converted per unit time. In the SI units, the unit of power is the watt, equal to one joule per second. Other units are, for example, 1 hp (one horsepower; 1 hp = 735.5 W) and then derived units such as kW — kilowatt.

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Do you have homework that you need help solving? Ask a question, and we will try to solve it.

See also more information on Wikipedia.

physics word problems with solutions about power

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v(h)=sinx

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Registered: 30.01.2006

From: University of Michigan, Ann Arbor

Posted: Sunday 31st of Dec 12:12  

 


I am searching for someone who can assist me with my math. I have a very important project coming up and need help in physics word problems with solutions about power and inverse matrices. I need help with topics covered in Algebra 2 class and seek help to master everything that I need to know so I can improve my grades.
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ameich

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Registered: 21.03.2005

From: Prague, Czech Republic

Posted: Monday 01st of Jan 11:08  

 


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SanG

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Registered: 31.08.2001

From: Beautiful Northwest Lower Michigan

Posted: Tuesday 02nd of Jan 18:10  

 


I agree. Stress will lead you to doom . Algebrator is a very handy tool. You don’t need to be a computer pro in order to use it. Its easy to use, and it works great.
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Galv

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Registered: 17.09.2001

From: Albuquerque, NM

Posted: Thursday 04th of Jan 11:49  

 


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3Di

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Registered: 04.04.2005

From: 45°26′ N, 09°10′ E

Posted: Friday 05th of Jan 12:08  

 


Yes I’m sure. This is tried and tested. Here: https://algbera.com/algebra-1.html. Try to make use of it. You’ll be improving your solving abilities way faster than just by reading tutorials.
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sxAoc

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Registered: 16.01.2002

From: Australia

Posted: Saturday 06th of Jan 21:35  

 


I suggest using Algebrator. It not only assists you with your math problems, but also displays all the required steps in detail so that you can improve the understanding of the subject.
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Are you familiar with exponents (powers)? Do you know for what and how they are used? Today, we are going to see an example that will help you to solve problems with exponents or powers.

If you need to review what powers are before learning how to use them in a word problem, you can check out our previous posts:

  • Powers in math
  • Powers: What They are and What They are for
  • Powers of base 10, base 100 and numbers followed by zeros

Exponents word problem

exponents

Lerna’s Hydra is a mythological character that appears in some stories such as the 12 Tasks of Hercules. The Hydra was a one-headed monster but when it is cut off, 2 more heads grow in its place. If a hero tried to conquer it by cutting off all of its heads every day, how many heads would the Hydra have on the third day? And at the end of 10 days of trying to kill it?

We are going to solve the first question in this problem by considering:

The first day, upon cutting the head off, the monster had two heads.

The second day, upon cutting both heads off, they doubled: 2 x 2 = 4 heads.

The third day, the heads doubled again: 2 x 2 x 2 = 8 heads

Finally, in order to know how many heads it had on the third day, we have multiplied by two, three times.

In order to solve the second problem, we had to do the same procedure but it’s a little larger scale.

In order to know how many heads the monster had in 10 days, we must do the following operation:

2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2

It is a lot, right? For this, it will be easier to write if we use exponents, expressing the same operation in the following style:

exponent

What do you think? It might not be actually easier to find the answer (without a calculator), but isn’t is neat to be able to use an exponent to write such a long multiplication problem in such a simple way?

We invite you to register in Smartick and try it for free if you want to continue learning math and how to solve problems.

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It is shown that the subgroup membership problem for a virtually free group can be decided in polynomial time where all group elements are represented by so-called power words, i.e., words of the

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