Word for last in line - Word и Excel - помощь в работе с программами

For example i have a file:

$ cat file

i am the first example.

i am the second line.

i do a question about a file.

and i need:

example, line, file

i intent with «awk» but the problem is that the words are in different space

asked May 17, 2013 at 20:02

Try

$ awk 'NF>1{print $NF}' file
example.
line.
file.

To get the result in one line as in your example, try:

{
    sub(/./, ",", $NF)
    str = str$NF
}
END { print str }

output:

$ awk -f script.awk file
example, line, file,

Pure bash:

$ while read line; do [ -z "$line" ] && continue ;echo ${line##* }; done < file
example.
line.
file.

answered May 17, 2013 at 20:05

Fredrik PihlFredrik Pihl

44.2k7 gold badges83 silver badges130 bronze badges

You can do it easily with grep:

grep -oE '[^ ]+$' file

(-E use extended regex; -o output only the matched text instead of the full line)

answered May 18, 2013 at 5:05

ricirici

232k28 gold badges234 silver badges338 bronze badges

You can do something like this in awk:

awk '{ print $NF }'

Edit: To avoid empty line :

awk 'NF{ print $NF }'

P….

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answered May 17, 2013 at 20:05

Hal CanaryHal Canary

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Another way of doing this in plain bash is making use of the rev command like this:

cat file | rev | cut -d" " -f1 | rev | tr -d "." | tr "n" ","

Basically, you reverse the lines of the file, then split them with cut using space as the delimiter, take the first field that cut produces and then you reverse the token again, use tr -d to delete unwanted chars and tr again to replace newline chars with ,

Also, you can avoid the first cat by doing:

rev < file | cut -d" " -f1 | rev | tr -d "." | tr "n" ","

answered May 18, 2013 at 0:09

higuarohiguaro

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tldr;

$ awk '{print $NF}' file.txt | paste -sd, | sed 's/,/, /g'

For a file like this

$ cat file.txt
The quick brown fox
jumps over
the lazy dog.

the given command will print

fox, over, dog.

How it works:

awk '{print $NF}' : prints the last field of every line
paste -sd, : reads stdin serially (-s, one file at a time) and writes fields comma-delimited (-d,)
sed 's/,/, /g' : substitutes "," with ", " globally (for all instances)

References:

https://linux.die.net/man/1/awk
https://linux.die.net/man/1/paste
https://linux.die.net/man/1/sed

answered Mar 16, 2016 at 17:50

rubicksrubicks

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there are many ways. as awk solutions shows, it’s the clean solution

sed solution is to delete anything till the last space. So if there is no space at the end, it should work

sed 's/.* //g' <file>

you can avoid sed also and go for a while loop.

while read line
do [ -z "$line" ] && continue ;
echo $line|rev|cut -f1 -d' '|rev
done < file

it reads a line, reveres it, cuts the first (i.e. last in the original) and restores back

the same can be done in a pure bash way

while read line
do [ -z "$line" ] && continue ;
echo ${line##* }
done < file

it is called parameter expansion

answered May 17, 2013 at 20:26

abasuabasu

2,44419 silver badges22 bronze badges

If you want to start a perl one-liner for last word:

perl -lane 'print "$F[-1]"'

… where -a gives autosplit into @F and $F[-1] is the last element.

To turn into list with commas:

perl -ane 'print "$F[-1]" . (eof() ? "n":",")'

answered May 20, 2022 at 20:58

steveslivastevesliva

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I’m attempting to take the last word or phrase using grep for a specific pattern. In this example, it would be the from the last comma to the end of the line:

Blah,3,33,56,5,Foo 30,,,,,,,3,Great Value

And so the wanted output for that line would be «Great Value». All the lines are different lengths as well, but always have a single comma preceding the last words.

Basically, I would like to simply output from the last comma to the end of the line. Thank you!

asked Jan 25, 2017 at 3:51

Here:

grep -o '[^,]+$'

[^,]+ matches one or more characters that are not , at the end of the line ($)
-o prints only the matched portion

Example:

% grep -o '[^,]+$' <<<'Blah,3,33,56,5,Foo 30,,,,,,,3,Great Value'
Great Value

answered Jan 25, 2017 at 3:54

heemaylheemayl

53.8k8 gold badges121 silver badges139 bronze badges

Always like to see an awk solution so here it is (upvoted the proper solution!):

% awk -F, '{print $NF}'  <<<'Blah,3,33,56,5,Foo 30,,,,,,,3,Great Value'
Great Value

answered Jan 25, 2017 at 5:16

Paul EvansPaul Evans

8986 silver badges8 bronze badges

May be this will give you the desired output

Command :

#!/bin/bash
echo "Blah,3,33,56,5,Foo 30,,,,,,,3,Great Value" | rev | awk -F',' '{ print $1 }' | rev

Output :

Great Value

Tested on this website : https://rextester.com/KNMI75463

answered Nov 27, 2020 at 20:14

codeholic24codeholic24

2973 silver badges14 bronze badges

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@echo off
findstr /N . input.txt | findstr /I ^2.*alive$ > NUL    
IF %ERRORLEVEL% EQU 0 (Echo Hi) ELSE (Echo Hello)
pause

This batch reads in your text file with the /N switch, wich puts a number in front of every line, like:

1:This is a test,
2:and I am alive
3:Not?

The new text is piped to the second findstr, which uses the RegEx pattern ^2.*alive$ to find a line which begins with 2 and ends with alive. That was the hard part.

Since findstr sets its errorlevel to 0 if at least one match is found, we can use a simple IF statement to echo «Hi» or «Hello».

Batch in detail

findstr searches for strings in files
/N puts a line number in front of every line
. is a wildcard for any single character. It tells findstr to search for everything
| is the pipe command. The output from the first command is passed as input for the second one
/I tells findstr to search case-insensitive so «Alive» and «alive» are both found
^ is a RegEx term and stands for a line beginning
.* is a RegEx term and stands for an indefinite number of character
$ is a RegEx term and stands for a line ending
> NUL hides the findstr output so the matching line isn’t displayed in the CMD window
IF condition (command) ELSE (command) is a simple IF condition
%ERRORLEVEL% EQU 0 is the exit code of findstr. «EQU» stands for «equel»

Edit (example taken from OP’ comment below)

Your «Alive» isn’t at the 2nd line. Its the 5th
After «Alive» are three spaces in your example so alive$doesn’t match

Change ^2.*alive$ to 5.*alive. Or even better ^5.* Alive $
Note the spaces.

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Visual Basic
Visual Basic 6 and Earlier
Getting the last word in each line

May 8th, 2001, 12:55 PM

#1

Thread Starter

Addicted Member

Getting the last word in each line

i need to get the last word in every line in a textbox (in my case it would always be 25 or less)

i thought if i could decleare a variable and get each line in each variable:

Dim LastWord (1 to (txtInput.lines)) as string, X as integer
x=0
do
Lastword(x)=line input (txtInput.text)
x=X+1
on error exit do (does this work?)
loop

i know this wont work, but i guess you get the idea what im thinking of

and then i could use the InStrRev function to get the last word

Thanks in Advance
SUMMER IS HERE !!!!
May 8th, 2001, 01:21 PM

#2
Frenzied Member
You could do this with each string. Please note that I’ve used small bits of your code, no looping, no I/O, etc.
Code:

Dim strAry As Variant strAry = Split(txtInput.text, " ", -1) ' get all words LastWord(x) = strAry(UBound(strAry))
May 8th, 2001, 04:50 PM

#3

Thread Starter

Addicted Member

I get an error (9) «Subscript out of range»
using this code:

Dim strAry As Variant, LastWord(1 To 25) As String, X As Integer

strAry = Split(txtInput.Text, » «, -1) ‘ get all words
LastWord(X) = strAry(UBound(strAry))

the error points at the last sentence
May 8th, 2001, 05:03 PM

#4
<?>
you should show the complete code..where is x coming from…
‘no problem with this

Code:

Private Sub Form_Load() txtInput.Text = "to have any idea of how this works is beyond me." Dim strAry As Variant Dim LastWord(1 To 25) As String, X As Integer strAry = Split(txtInput.Text, " ") ' get all words LastWord(UBound(LastWord)) = strAry(UBound(strAry)) MsgBox LastWord(UBound(LastWord)) End Sub
«A myth is not the succession of individual images,
but an integerated meaningful entity,
reflecting a distinct aspect of the real world.»
___ Adolf Jensen
May 8th, 2001, 05:04 PM

#5

<?>

Never mind, I just read the original question…
back in a bit.

«A myth is not the succession of individual images,
but an integerated meaningful entity,
reflecting a distinct aspect of the real world.»
___ Adolf Jensen
May 8th, 2001, 05:12 PM

#6

Thread Starter

Addicted Member

that did work Thanks!
and this is all the code i got at the moment

but what does really ubound do? and variant?
May 8th, 2001, 05:15 PM

#7

Thread Starter

Addicted Member

ahh…. one more thing… your code only gets the last word in the textbox…. i need to get the last word in every line

May 8th, 2001, 05:37 PM

<?>

Like I said..back in a bit

I attached an example of the code.
Code:
Option Explicit

'uses Command1, txtInput, List1

Private Sub Command1_Click()
    
    Dim LWord()    'array for last words
    Dim tLine As Variant  'used in split the lines
    Dim strArr As Variant 'used in split the text
    
    Dim i As Integer
    strArr = Split(txtInput.Text, vbCrLf) 'get each line into an array
     
    For i = 0 To UBound(strArr)
      ReDim Preserve LWord(i)  'keep the contents each time you dim it
      tLine = Split(strArr(i)) 'split on spaces
      LWord(i) = tLine(UBound(tLine))   'get the last word
    Next i
    
    'display your array of last words in a list box
    For i = LBound(LWord) To UBound(LWord)
        List1.AddItem LWord(i)
    Next i

End Sub

Private Sub Form_Load()
txtInput = ""   'clear box
'load box for testing purposes
Dim X As String, i As Integer
'don't leave an extra vbcrlf in the text box
    For i = 1 To 25
       If i <> 25 Then
       X = "to have any idea of how this works is beyond me." & i & vbCrLf
       Else
       X = "to have any idea of how this works is beyond me." & i
       End If
       txtInput = txtInput & X
    Next i
     
End Sub

«A myth is not the succession of individual images,
but an integerated meaningful entity,
reflecting a distinct aspect of the real world.»
___ Adolf Jensen

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Visual Basic 6 and Earlier
Getting the last word in each line

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Getting the last word in each line

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<?>

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