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Содержание
- Объяснение Type Mismatch Error
- Использование отладчика
- Присвоение строки числу
- Недействительная дата
- Ошибка ячейки
- Неверные данные ячейки
- Имя модуля
- Различные типы объектов
- Коллекция Sheets
- Массивы и диапазоны
- Заключение
Объяснение Type Mismatch Error
Type Mismatch Error VBA возникает при попытке назначить значение между двумя различными типами переменных.
Ошибка отображается как:
run-time error 13 – Type mismatch
Например, если вы пытаетесь поместить текст в целочисленную переменную Long или пытаетесь поместить число в переменную Date.
Давайте посмотрим на конкретный пример. Представьте, что у нас есть переменная с именем Total, которая является длинным целым числом Long.
Если мы попытаемся поместить текст в переменную, мы получим Type Mismatch Error VBA (т.е. VBA Error 13).
Sub TypeMismatchStroka() ' Объявите переменную типа long integer Dim total As Long ' Назначение строки приведет к Type Mismatch Error total = "Иван" End Sub
Давайте посмотрим на другой пример. На этот раз у нас есть переменная ReportDate типа Date.
Если мы попытаемся поместить в эту переменную не дату, мы получим Type Mismatch Error VBA.
Sub TypeMismatchData() ' Объявите переменную типа Date Dim ReportDate As Date ' Назначение числа вызывает Type Mismatch Error ReportDate = "21-22" End Sub
В целом, VBA часто прощает, когда вы назначаете неправильный тип значения переменной, например:
Dim x As Long ' VBA преобразует в целое число 100 x = 99.66 ' VBA преобразует в целое число 66 x = "66"
Тем не менее, есть некоторые преобразования, которые VBA не может сделать:
Dim x As Long ' Type Mismatch Error x = "66a"
Простой способ объяснить Type Mismatch Error VBA состоит в том, что элементы по обе стороны от равных оценивают другой тип.
При возникновении Type Mismatch Error это часто не так просто, как в этих примерах. В этих более сложных случаях мы можем использовать средства отладки, чтобы помочь нам устранить ошибку.
Использование отладчика
В VBA есть несколько очень мощных инструментов для поиска ошибок. Инструменты отладки позволяют приостановить выполнение кода и проверить значения в текущих переменных.
Вы можете использовать следующие шаги, чтобы помочь вам устранить любую Type Mismatch Error VBA.
- Запустите код, чтобы появилась ошибка.
- Нажмите Debug в диалоговом окне ошибки. Это выделит строку с ошибкой.
- Выберите View-> Watch из меню, если окно просмотра не видно.
- Выделите переменную слева от equals и перетащите ее в окно Watch.
- Выделите все справа от равных и перетащите его в окно Watch.
- Проверьте значения и типы каждого.
- Вы можете сузить ошибку, изучив отдельные части правой стороны.
Следующее видео показывает, как это сделать.
На скриншоте ниже вы можете увидеть типы в окне просмотра.
Используя окно просмотра, вы можете проверить различные части строки кода с ошибкой. Затем вы можете легко увидеть, что это за типы переменных.
В следующих разделах показаны различные способы возникновения Type Mismatch Error VBA.
Присвоение строки числу
Как мы уже видели, попытка поместить текст в числовую переменную может привести к Type Mismatch Error VBA.
Ниже приведены некоторые примеры, которые могут вызвать ошибку:
Sub TextErrors() ' Long - длинное целое число Dim l As Long l = "a" ' Double - десятичное число Dim d As Double d = "a" ' Валюта - 4-х значное число Dim c As Currency c = "a" Dim d As Double ' Несоответствие типов, если ячейка содержит текст d = Range("A1").Value End Sub
Недействительная дата
VBA очень гибок в назначении даты переменной даты. Если вы поставите месяц в неправильном порядке или пропустите день, VBA все равно сделает все возможное, чтобы удовлетворить вас.
В следующих примерах кода показаны все допустимые способы назначения даты, за которыми следуют случаи, которые могут привести к Type Mismatch Error VBA.
Sub DateMismatch() Dim curDate As Date ' VBA сделает все возможное для вас ' - Все они действительны curDate = "12/12/2016" curDate = "12-12-2016" curDate = #12/12/2016# curDate = "11/Aug/2016" curDate = "11/Augu/2016" curDate = "11/Augus/2016" curDate = "11/August/2016" curDate = "19/11/2016" curDate = "11/19/2016" curDate = "1/1" curDate = "1/2016" ' Type Mismatch Error curDate = "19/19/2016" curDate = "19/Au/2016" curDate = "19/Augusta/2016" curDate = "August" curDate = "Какой-то случайный текст" End Sub
Ошибка ячейки
Тонкая причина Type Mismatch Error VBA — это когда вы читаете из ячейки с ошибкой, например:
Если вы попытаетесь прочитать из этой ячейки, вы получите Type Mismatch Error.
Dim sText As String ' Type Mismatch Error, если ячейка содержит ошибку sText = Sheet1.Range("A1").Value
Чтобы устранить эту ошибку, вы можете проверить ячейку с помощью IsError следующим образом.
Dim sText As String If IsError(Sheet1.Range("A1").Value) = False Then sText = Sheet1.Range("A1").Value End If
Однако проверка всех ячеек на наличие ошибок невозможна и сделает ваш код громоздким. Лучший способ — сначала проверить лист на наличие ошибок, а если ошибки найдены, сообщить об этом пользователю.
Вы можете использовать следующую функцию, чтобы сделать это:
Function CheckForErrors(rg As Range) As Long On Error Resume Next CheckForErrors = rg.SpecialCells(xlCellTypeFormulas, xlErrors).Count End Function
Ниже приведен пример использования этого кода.
Sub DoStuff() If CheckForErrors(Sheet1.Range("A1:Z1000")) > 0 Then MsgBox "На листе есть ошибки. Пожалуйста, исправьте и запустите макрос снова." Exit Sub End If ' Продолжайте здесь, если нет ошибок End Sub
Неверные данные ячейки
Как мы видели, размещение неверного типа значения в переменной вызывает Type Mismatch Error VBA. Очень распространенная причина — это когда значение в ячейке имеет неправильный тип.
Пользователь может поместить текст, такой как «Нет», в числовое поле, не осознавая, что это приведет к Type Mismatch Error в коде.
Если мы прочитаем эти данные в числовую переменную, то получим
Type Mismatch Error VBA.
Dim rg As Range Set rg = Sheet1.Range("B2:B5") Dim cell As Range, Amount As Long For Each cell In rg ' Ошибка при достижении ячейки с текстом «Нет» Amount = cell.Value Next rg
Вы можете использовать следующую функцию, чтобы проверить наличие нечисловых ячеек, прежде чем использовать данные.
Function CheckForTextCells(rg As Range) As Long ' Подсчет числовых ячеек If rg.Count = rg.SpecialCells(xlCellTypeConstants, xlNumbers).Count Then CheckForTextCells = True End If End Function
Вы можете использовать это так:
Sub IspolzovanieCells() If CheckForTextCells(Sheet1.Range("B2:B6").Value) = False Then MsgBox "Одна из ячеек не числовая. Пожалуйста, исправьте перед запуском макроса" Exit Sub End If ' Продолжайте здесь, если нет ошибок End Sub
Имя модуля
Если вы используете имя модуля в своем коде, это может привести к
Type Mismatch Error VBA. Однако в этом случае причина может быть не очевидной.
Например, допустим, у вас есть модуль с именем «Module1». Выполнение следующего кода приведет к о
Type Mismatch Error VBA.
Sub IspolzovanieImeniModulya() ' Type Mismatch Error Debug.Print module1 End Sub
Различные типы объектов
До сих пор мы рассматривали в основном переменные. Мы обычно называем переменные основными типами данных.
Они используются для хранения одного значения в памяти.
В VBA у нас также есть объекты, которые являются более сложными. Примерами являются объекты Workbook, Worksheet, Range и Chart.
Если мы назначаем один из этих типов, мы должны убедиться, что назначаемый элемент является объектом того же типа. Например:
Sub IspolzovanieWorksheet() Dim wk As Worksheet ' действительный Set wk = ThisWorkbook.Worksheets(1) ' Type Mismatch Error ' Левая сторона - это worksheet - правая сторона - это workbook Set wk = Workbooks(1) End Sub
Коллекция Sheets
В VBA объект рабочей книги имеет две коллекции — Sheets и Worksheets. Есть очень тонкая разница.
- Worksheets — сборник рабочих листов в Workbook
- Sheets — сборник рабочих листов и диаграммных листов в Workbook
Лист диаграммы создается, когда вы перемещаете диаграмму на собственный лист, щелкая правой кнопкой мыши на диаграмме и выбирая «Переместить».
Если вы читаете коллекцию Sheets с помощью переменной Worksheet, она будет работать нормально, если у вас нет рабочей таблицы.
Если у вас есть лист диаграммы, вы получите
Type Mismatch Error VBA.
В следующем коде Type Mismatch Error появится в строке «Next sh», если рабочая книга содержит лист с диаграммой.
Sub SheetsError() Dim sh As Worksheet For Each sh In ThisWorkbook.Sheets Debug.Print sh.Name Next sh End Sub
Массивы и диапазоны
Вы можете назначить диапазон массиву и наоборот. На самом деле это очень быстрый способ чтения данных.
Sub IspolzovanieMassiva() Dim arr As Variant ' Присвойте диапазон массиву arr = Sheet1.Range("A1:B2").Value ' Выведите значение в строку 1, столбец 1 Debug.Print arr(1, 1) End Sub
Проблема возникает, если ваш диапазон имеет только одну ячейку. В этом случае VBA не преобразует arr в массив.
Если вы попытаетесь использовать его как массив, вы получите
Type Mismatch Error .
Sub OshibkaIspolzovanieMassiva() Dim arr As Variant ' Присвойте диапазон массиву arr = Sheet1.Range("A1").Value ' Здесь будет происходить Type Mismatch Error Debug.Print arr(1, 1) End Sub
В этом сценарии вы можете использовать функцию IsArray, чтобы проверить, является ли arr массивом.
Sub IspolzovanieMassivaIf() Dim arr As Variant ' Присвойте диапазон массиву arr = Sheet1.Range("A1").Value ' Здесь будет происходить Type Mismatch Error If IsArray(arr) Then Debug.Print arr(1, 1) Else Debug.Print arr End If End Sub
Заключение
На этом мы завершаем статью об Type Mismatch Error VBA. Если у вас есть ошибка несоответствия, которая не раскрыта, пожалуйста, дайте мне знать в комментариях.
I created a macro for a file and first it was working fine, but today I’ve been opening and restarting the file and macro hundreds of times and I’m always getting the following error:
Excel VBA Run-time error ’13’ Type mismatch
I didn’t change anything in the macro and don’t know why am I getting the error. Furthermore it takes ages to update the macro every time I put it running (the macro has to run about 9000 rows).
The error is on the line in the between ** **.
VBA:
Sub k()
Dim x As Integer, i As Integer, a As Integer
Dim name As String
name = InputBox("Please insert the name of the sheet")
i = 1
Sheets(name).Cells(4, 58) = Sheets(name).Cells(4, 57)
x = Sheets(name).Cells(4, 57).Value
Do While Not IsEmpty(Sheets(name).Cells(i + 4, 57))
a = 0
If Sheets(name).Cells(4 + i, 57) <> x Then
If Sheets(name).Cells(4 + i, 57) <> 0 Then
If Sheets(name).Cells(4 + i, 57) = 3 Then
a = x
Sheets(name).Cells(4 + i, 58) = Sheets(name).Cells(4 + i, 57) - x
x = Cells(4 + i, 57) - x
End If
**Sheets(name).Cells(4 + i, 58) = Sheets(name).Cells(4 + i, 57) - a**
x = Sheets(name).Cells(4 + i, 57) - a
Else
Cells(4 + i, 58) = ""
End If
Else
Cells(4 + i, 58) = ""
End If
i = i + 1
Loop
End Sub
I’m using excel 2010 on windows 7.
Vega
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asked Jan 16, 2012 at 19:52
1
You would get a type mismatch if Sheets(name).Cells(4 + i, 57)
contains a non-numeric value. You should validate the fields before you assume they are numbers and try to subtract from them.
Also, you should enable Option Strict
so you are forced to explicitly convert your variables before trying to perform type-dependent operations on them such as subtraction. That will help you identify and eliminate issues in the future, too.
Unfortunately Option Strict
is for VB.NET only. Still, you should look up best practices for explicit data type conversions in VBA.
Update:
If you are trying to go for the quick fix of your code, however, wrap the **
line and the one following it in the following condition:
If IsNumeric(Sheets(name).Cells(4 + i, 57))
Sheets(name).Cells(4 + i, 58) = Sheets(name).Cells(4 + i, 57) - a
x = Sheets(name).Cells(4 + i, 57) - a
End If
Note that your x
value may not contain its expected value in the next iteration, however.
answered Jan 16, 2012 at 19:55
Devin BurkeDevin Burke
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5
Thank you guys for all your help! Finally I was able to make it work perfectly thanks to a friend and also you!
Here is the final code so you can also see how we solve it.
Thanks again!
Option Explicit
Sub k()
Dim x As Integer, i As Integer, a As Integer
Dim name As String
'name = InputBox("Please insert the name of the sheet")
i = 1
name = "Reserva"
Sheets(name).Cells(4, 57) = Sheets(name).Cells(4, 56)
On Error GoTo fim
x = Sheets(name).Cells(4, 56).Value
Application.Calculation = xlCalculationManual
Do While Not IsEmpty(Sheets(name).Cells(i + 4, 56))
a = 0
If Sheets(name).Cells(4 + i, 56) <> x Then
If Sheets(name).Cells(4 + i, 56) <> 0 Then
If Sheets(name).Cells(4 + i, 56) = 3 Then
a = x
Sheets(name).Cells(4 + i, 57) = Sheets(name).Cells(4 + i, 56) - x
x = Cells(4 + i, 56) - x
End If
Sheets(name).Cells(4 + i, 57) = Sheets(name).Cells(4 + i, 56) - a
x = Sheets(name).Cells(4 + i, 56) - a
Else
Cells(4 + i, 57) = ""
End If
Else
Cells(4 + i, 57) = ""
End If
i = i + 1
Loop
Application.Calculation = xlCalculationAutomatic
Exit Sub
fim:
MsgBox Err.Description
Application.Calculation = xlCalculationAutomatic
End Sub
bpeterson76
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answered Jan 17, 2012 at 16:50
DiogoDiogo
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1
Diogo
Justin has given you some very fine tips
You will also get that error if the cell where you are performing the calculation has an error resulting from a formula.
For example if Cell A1 has #DIV/0! error then you will get «Excel VBA Run-time error ’13’ Type mismatch» when performing this code
Sheets("Sheet1").Range("A1").Value - 1
I have made some slight changes to your code. Could you please test it for me? Copy the code with the line numbers as I have deliberately put them there.
Option Explicit
Sub Sample()
Dim ws As Worksheet
Dim x As Integer, i As Integer, a As Integer, y As Integer
Dim name As String
Dim lastRow As Long
10 On Error GoTo Whoa
20 Application.ScreenUpdating = False
30 name = InputBox("Please insert the name of the sheet")
40 If Len(Trim(name)) = 0 Then Exit Sub
50 Set ws = Sheets(name)
60 With ws
70 If Not IsError(.Range("BE4").Value) Then
80 x = Val(.Range("BE4").Value)
90 Else
100 MsgBox "Please check the value of cell BE4. It seems to have an error"
110 GoTo LetsContinue
120 End If
130 .Range("BF4").Value = x
140 lastRow = .Range("BE" & Rows.Count).End(xlUp).Row
150 For i = 5 To lastRow
160 If IsError(.Range("BE" & i)) Then
170 MsgBox "Please check the value of cell BE" & i & ". It seems to have an error"
180 GoTo LetsContinue
190 End If
200 a = 0: y = Val(.Range("BE" & i))
210 If y <> x Then
220 If y <> 0 Then
230 If y = 3 Then
240 a = x
250 .Range("BF" & i) = Val(.Range("BE" & i)) - x
260 x = Val(.Range("BE" & i)) - x
270 End If
280 .Range("BF" & i) = Val(.Range("BE" & i)) - a
290 x = Val(.Range("BE" & i)) - a
300 Else
310 .Range("BF" & i).ClearContents
320 End If
330 Else
340 .Range("BF" & i).ClearContents
350 End If
360 Next i
370 End With
LetsContinue:
380 Application.ScreenUpdating = True
390 Exit Sub
Whoa:
400 MsgBox "Error Description :" & Err.Description & vbNewLine & _
"Error at line : " & Erl
410 Resume LetsContinue
End Sub
answered Jan 16, 2012 at 23:15
Siddharth RoutSiddharth Rout
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3
For future readers:
This function was abending in Run-time error '13': Type mismatch
Function fnIsNumber(Value) As Boolean
fnIsNumber = Evaluate("ISNUMBER(0+""" & Value & """)")
End Function
In my case, the function was failing when it ran into a #DIV/0!
or N/A
value.
To solve it, I had to do this:
Function fnIsNumber(Value) As Boolean
If CStr(Value) = "Error 2007" Then '<===== This is the important line
fnIsNumber = False
Else
fnIsNumber = Evaluate("ISNUMBER(0+""" & Value & """)")
End If
End Function
answered Jun 21, 2018 at 15:45
cssyphuscssyphus
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Sub HighlightSpecificValue()
'PURPOSE: Highlight all cells containing a specified values
Dim fnd As String, FirstFound As String
Dim FoundCell As Range, rng As Range
Dim myRange As Range, LastCell As Range
'What value do you want to find?
fnd = InputBox("I want to hightlight cells containing...", "Highlight")
'End Macro if Cancel Button is Clicked or no Text is Entered
If fnd = vbNullString Then Exit Sub
Set myRange = ActiveSheet.UsedRange
Set LastCell = myRange.Cells(myRange.Cells.Count)
enter code here
Set FoundCell = myRange.Find(what:=fnd, after:=LastCell)
'Test to see if anything was found
If Not FoundCell Is Nothing Then
FirstFound = FoundCell.Address
Else
GoTo NothingFound
End If
Set rng = FoundCell
'Loop until cycled through all unique finds
Do Until FoundCell Is Nothing
'Find next cell with fnd value
Set FoundCell = myRange.FindNext(after:=FoundCell)
'Add found cell to rng range variable
Set rng = Union(rng, FoundCell)
'Test to see if cycled through to first found cell
If FoundCell.Address = FirstFound Then Exit Do
Loop
'Highlight Found cells yellow
rng.Interior.Color = RGB(255, 255, 0)
Dim fnd1 As String
fnd1 = "Rah"
'Condition highlighting
Set FoundCell = myRange.FindNext(after:=FoundCell)
If FoundCell.Value("rah") Then
rng.Interior.Color = RGB(255, 0, 0)
ElseIf FoundCell.Value("Nav") Then
rng.Interior.Color = RGB(0, 0, 255)
End If
'Report Out Message
MsgBox rng.Cells.Count & " cell(s) were found containing: " & fnd
Exit Sub
'Error Handler
NothingFound:
MsgBox "No cells containing: " & fnd & " were found in this worksheet"
End Sub
Neil
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answered Oct 9, 2015 at 10:10
I had the same problem as you mentioned here above and my code was doing great all day yesterday.
I kept on programming this morning and when I opened my application (my file with an Auto_Open sub), I got the Run-time error ’13’ Type mismatch, I went on the web to find answers, I tried a lot of things, modifications and at one point I remembered that I read somewhere about «Ghost» data that stays in a cell even if we don’t see it.
My code do only data transfer from one file I opened previously to another and Sum it. My code stopped at the third SheetTab (So it went right for the 2 previous SheetTab where the same code went without stopping) with the Type mismatch message. And it does that every time at the same SheetTab when I restart my code.
So I selected the cell where it stopped, manually entered 0,00 (Because the Type mismatch comes from a Summation variables declared in a DIM as Double) and copied that cell in all the subsequent cells where the same problem occurred. It solved the problem. Never had the message again. Nothing to do with my code but the «Ghost» or data from the past. It is like when you want to use the Control+End and Excel takes you where you had data once and deleted it. Had to «Save» and close the file when you wanted to use the Control+End to make sure Excel pointed you to the right cell.
TylerH
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answered Oct 11, 2013 at 19:14
This error occurs when the input variable type is wrong. You probably have written a formula in Cells(4 + i, 57)
that instead of =0
, the formula = ""
have used. So when running this error is displayed. Because empty string is not equal to zero.
answered Dec 13, 2016 at 21:12
gadolfgadolf
1,00511 silver badges19 bronze badges
Summary:
This post is written with the main prospective of providing you all with ample amount of detail regarding Excel runtime error 13. So go through this complete guide to know how to fix runtime error 13 type mismatch.
In our earlier blogs, we have described the commonly found Excel file runtime error 1004, 32809 and 57121. Today in this article we are describing another Excel file runtime error 13.
Run-time error ‘13’: Type Mismatch usually occurs meanwhile the code is executed in Excel. As a result of this, you may get terminated every time from all the ongoing activities on your Excel application.
This run time error 13 also put an adverse effect on XLS/XLSX files. So before this Excel Type Mismatch error damages your Excel files, fix it out immediately with the given fixes.
Apart from that, there are many reasons behind getting the Excel file runtime error 13 when the Excel file gets corrupted this starts showing runtime error.
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Error Detail:
Error code: Run-time error ‘13’
Declaration: Excel Type Mismatch error
Here is the screenshot of this error:
Why Am I Getting Excel Runtime Error 13 Type Mismatch?
Following are some reasons for run time error 13 type mismatch:
- When multiple methods or files require to starts a program that uses Visual Basic (VB) environment
- Runtime error 13 often occurs when mismatches occur within the software applications which you require to use.
- Due to virus and malware infection as this corrupts the Windows system files or Excel-related files.
- When you tap on the function or macro present on the menu which is created by another Macro then also you will receive the same run time error 13.
- The runtime error commonly occurs due to the conflict between the software and the operating system.
- Due to the corrupt or incomplete installation of Microsoft Excel software.
- The Run-time Error 13 appears when the users try to run VBA code that includes data types that are not matched correctly. Thus it starts displaying Runtime error 13 type mismatch.
- Due to conflict with other programs while opening the VBA Excel file.
Well, these are some of the common reasons for getting the Excel file runtime error 13.
How To Fix Excel Runtime Error 13 Type Mismatch?
Learn how to Fix Excel Runtime Error 13 Type Mismatch.
1: Using Open and Repair Utility
2. Uninstall The Program
3. Scan For Virus/Malware
4. Recover Missing Macros
5. Run The ‘Regedit’ Command In CMD
6: Create New Disk Partition And Reinstall Windows
7: Use MS Excel Repair Tool
1: Using Open and Repair Utility
There is a ‘File Recovery’ mode within Excel which gets activated automatically when any corruption issue hits your worksheet or workbook.
But in some cases, Excel won’t offer this ‘File Recovery’ mode and at that time you need to use Excel inbuilt tool ‘Open and Repair’.
Using this inbuilt utility tool you can recover corrupted/damaged Excel files. Try the following steps to fix Visual Basic runtime error 13 type mismatch in Excel.
Here follow the steps to do so:
- In the File menu> click “Open”
- And select corrupt Excel file > from the drop-down list of open tab > select “Open and Repair”
- Lastly, click on the “Repair” button.
However, it is found that the inbuilt repair utility fails to repair the severely damaged Excel file.
2. Uninstall The Program
It is found some application and software causes the runtime error.
So, to fix the Excel file error, simply uninstall the problematic apps and programs.
- First, go to the Task Manager and stop the running programs.
- Then in the start menu > select Control Panel.
- In the Control Panel > choose Add or Remove Program.
- Here, you will get the list of installed programs on your PC.
- Then from the list select Microsoft Work.
- Click on uninstall to remove it from the PC.
Hope doing this will fix the Excel file Runtime error 13, but if not then follow the third solution.
3. Scan For Virus/Malware
Virus intrusion is quite a big problem for all Windows users, as it causes several issues for PC and Excel files.
This can be the great reason behind this Runtime 13 error. As viruses damage the core program file of MS Office which is important for the execution of Excel application.
This makes the file unreadable and starts generating the following error message: Visual Basic runtime error 13 type mismatch in Excel
To avoid this error, you need to remove all virus infections from your system using the reliable anti-virus removal tool.
Well, it is found that if your Windows operating system in having viruses and malware then this might corrupt Excel file and as a result, you start facing the runtime file error 13.
So, it is recommended to scan your system with the best antivirus program and make your system malware-free. Ultimately this will also fix runtime error 13.
4. Recover Missing Macros
Well, as it is found that users are getting the runtime error 13 due to the missing macros, So try to recover the missing Macros.
Here follow the steps to do so:
- Open the new Excel file > and set the calculation mode to Manual
- Now from the Tools menu select Macro > select Security > High option.
- If you are using Excel 2007, then click the Office button > Excel Options > Trust Center in the left panel
- And click on Trust Center Settings button > Macro Settings > Disable All Macros without Notification in the Macro Settings section > click OK twice.
- Now, open the corrupted workbook. If Excel opens the workbook a message appears that the macros are disabled.
- But if in case Excel shut down, then this method is not workable.
- Next press [Alt] + [F11] for opening the Visual Basic Editor (VBE).
- Make use of the Project Explorer (press [Ctrl]+R) > right-click a module > Export File.
- Type name and folder for the module > and repeat this step as many times as required to export the entire module.
- Finally, close the VBE and exit.
Now open the new blank workbook (or the recently constructed workbook that contains recovered data from the corrupted workbook) and import the modules.
5. Run The ‘Regedit’ Command In CMD
This Excel error 13 can also be fixed by running the ‘Regedit’ command in the command prompt.
- In the search menu of your system’s start menu type run command.
- Now in the opened run dialog box type “regedit” command. After that hit the OK
- This will open the registry editor. On its right side there is a ‘LoadApplnit_DLLs value.’ option, just make double-tap to it.
- Change the value from 1 to ‘0‘and then press the OK.
- Now take exit from this opened registry editor.
- After completing all this, restart your PC.
Making the above changes will definitely resolve the Runtime Error 13 Type Mismatch.
6: Create New Disk Partition And Reinstall Windows
If even after trying all the above-given fixes Excel type mismatched error still persists. In that case, the last option left here is to create the new partition and reinstall Windows.
- In your PC insert windows DVD/CD and after that begin the installation procedure.
- For installation, choose the language preference.
- Tap to the option” I accept” and then hit the NEXT
- Select the custom advance option and then choose the Disk O partition 1
- Now hit the delete> OK button.
- The same thing you have to repeat after selecting the Disk O partition 2.
- Now hit the delete> OK button to delete this too.
- After completing the deletion procedure, tap to create a new partition.
- Assign the disk size and tap to the Apply.
- Now choose the Disk 0 partition 2 and then hit the Formatting.
- After complete formatting, hit the NEXT button to continue.
Note: before attempting this procedure don’t forget to keep a complete backup of all your data.
However, if you are still facing the Excel Runtime file error 13 then make use of the third party automatic repair tool.
7: Use MS Excel Repair Tool
It is recommended to make use of the MS Excel Repair Tool. This is the best tool to repair all sort of issues, corruption, errors in Excel workbooks. This tool allows to easily restore all corrupt excel file including the charts, worksheet properties cell comments, and other important data.
* Free version of the product only previews recoverable data.
This is a unique tool to repair multiple excel files at one repair cycle and recovers the entire data in a preferred location. It is easy to use and compatible with both Windows as well as Mac operating systems.
Steps to Utilize MS Excel Repair Tool:
Final Verdict:
After reading the complete post you must have got enough idea on Visual Basic runtime error 13 type mismatch in Excel. Following the listed given fixes you are able to fix the Excel runtime file error 13.
I tried my best to provide ample information about the runtime error and possible workarounds that will help you to fix the Excel file error.
So, just make use of the solutions given and check whether the Excel error is fixed or not.
In case you have any additional workarounds that proved successful or questions concerning the ones presented, do tell us in the comments.
Hope you find this post informative and helpful.
Thanks for reading…!
Priyanka is an entrepreneur & content marketing expert. She writes tech blogs and has expertise in MS Office, Excel, and other tech subjects. Her distinctive art of presenting tech information in the easy-to-understand language is very impressive. When not writing, she loves unplanned travels.
Home / VBA / VBA Type Mismatch Error (Error 13)
Type Mismatch (Error 13) occurs when you try to specify a value to a variable that doesn’t match with its data type. In VBA, when you declare a variable you need to define its data type, and when you specify a value that is different from that data type you get the type mismatch error 13.
In this tutorial, we will see what the possible situations are where runtime error 13 can occurs while executing a code.
Type Mismatch Error with Date
In VBA, there is a specific data type to deal with dates and sometimes it happens when you using a variable to store a date and somehow the value you specify is different.
In the following code, I have declared a variable as the date and then I have specified the value from cell A1 where I am supposed to have a date only. But as you can see the date that I have in cell one is not in the correct format VBA is not able to identify it as a date.
Sub myMacro()
Dim iVal As Date
iVal = Range("A1").Value
End Sub
Type Mismatch Error with Number
You’re gonna have you can have the same error while dealing with numbers where you get a different value when you trying to specify a number to a variable.
In the following example, you have an error in cell A1 which is supposed to be a numeric value. So when you run the code, VBA shows you the runtime 13 error because it cannot identify the value as a number.
Sub myMacro()
Dim iNum As Long
iNum = Range("A6").Value
End Sub
Runtime Error 6 Overflow
In VBA, there are multiple data types to deal with numbers and each of these data types has a range of numbers that you can assign to it. But there is a problem when you specify a number that is out of the range of the data type.
In that case, we will show you runtime error 6 overflow which indicates you need to change the data type and the number you have specified is out of the range.
Other Situations When it can Occurs
There might be some other situations in that you could face the runtime error 14: Type Mismatch.
- When you assign a range to an array but that range only consists of a single cell.
- When you define a variable as an object but by writing the code you specify a different object to that variable.
- When you specify a variable as a worksheet but use sheets collection in the code or vice versa.
How to Fix Type Mismatch (Error 13)
The best way to deal with this error is to use to go to the statement to run a specific line of code or show a message box to the user when the error occurs. But you can also check the court step by step before executing it. For this, you need to use VBA’s debug tool, or you can also use the shortcut key F8.
In this Article
- VBA Type Mismatch Errors
- What is a Type Mismatch Error?
- Mismatch Error Caused by Worksheet Calculation
- Mismatch Error Caused by Entered Cell Values
- Mismatch Error Caused by Calling a Function or Sub Routine Using Parameters
- Mismatch Error Caused by using Conversion Functions in VBA Incorrectly
- General Prevention of Mismatch Errors
- Define your variables as Variant Type
- Use the OnError Command to Handle Errors
- Use the OnError Command to Supress Errors
- Converting the Data to a Data Type to Match the Declaration
- Testing Variables Within Your Code
- Objects and Mismatch Errors
VBA Type Mismatch Errors
What is a Type Mismatch Error?
A mismatch error can often occur when you run your VBA code. The error will stop your code from running completely and flag up by means of a message box that this error needs sorting out
Note that if you have not fully tested your code before distribution to users, this error message will be visible to users, and will cause a big loss of confidence in your Excel application. Unfortunately, users often do very peculiar things to an application and are often things that you as the developer never considered.
A type mismatch error occurs because you have defined a variable using the Dim statement as a certain type e.g. integer, date, and your code is trying to assign a value to the variable which is not acceptable e.g. text string assigned to an integer variable as in this example:
Here is an example:
Click on Debug and the offending line of code will be highlighted in yellow. There is no option on the error pop-up to continue, since this is a major error and there is no way the code can run any further.
In this particular case, the solution is to change the Dim statement to a variable type that works with the value that you are assigning to the variable. The code will work if you change the variable type to ‘String’, and you would probably want to change the variable name as well.
However, changing the variable type will need your project resetting, and you will have to run your code again right from the beginning again, which can be very annoying if a long procedure is involved
Mismatch Error Caused by Worksheet Calculation
The example above is a very simple one of how a mismatch error can be produced and, in this case, it is easily remedied
However, the cause of mismatch errors is usually far deeper than this, and is not so obvious when you are trying to debug your code.
As an example, suppose that you have written code to pick up a value in a certain position on a worksheet and it contains a calculation dependent other cells within the workbook (B1 in this example)
The worksheet looks like this example, with a formula to find a particular character within a string of text
From the user’s point of view, cell A1 is free format and they can enter any value that they want to. However, the formula is looking for an occurrence of the character ‘B’, and in this case it is not found so cell B1 has an error value.
The test code below will produce a mismatch error because a wrong value has been entered into cell A1
Sub TestMismatch()
Dim MyNumber As Integer
MyNumber = Sheets("Sheet1").Range("B1").Value
End Sub
The value in cell B1 has produced an error because the user has entered text into cell A1 which does not conform to what was expected and it does not contain the character ‘B’
The code tries to assign the value to the variable ‘MyNumber’ which has been defined to expect an integer, and so you get a mismatch error.
This is one of these examples where meticulously checking your code will not provide the answer. You also need to look on the worksheet where the value is coming from in order to find out why this is happening.
The problem is actually on the worksheet, and the formula in B1 needs changing so that error values are dealt with. You can do this by using the ‘IFERROR’ formula to provide a default value of 0 if the search character is not found
You can then incorporate code to check for a zero value, and to display a warning message to the user that the value in cell A1 is invalid
Sub TestMismatch()
Dim MyNumber As Integer
MyNumber = Sheets("Sheet1").Range("B1").Text
If MyNumber = 0 Then
MsgBox "Value at cell A1 is invalid", vbCritical
Exit Sub
End If
End Sub
You could also use data validation (Data Tools group on the Data tab of the ribbon) on the spreadsheet to stop the user doing whatever they liked and causing worksheet errors in the first place. Only allow them to enter values that will not cause worksheet errors.
You could write VBA code based on the Change event in the worksheet to check what has been entered.
Also lock and password protect the worksheet, so that the invalid data cannot be entered
Mismatch Error Caused by Entered Cell Values
Mismatch errors can be caused in your code by bringing in normal values from a worksheet (non-error), but where the user has entered an unexpected value e.g. a text value when you were expecting a number. They may have decided to insert a row within a range of numbers so that they can put a note into a cell explaining something about the number. After all, the user has no idea how your code works and that they have just thrown the whole thing out of kilter by entering their note.
The example code below creates a simple array called ‘MyNumber’ defined with integer values
The code then iterates through a range of the cells from A1 to A7, assigning the cell values into the array, using a variable ‘Coun’ to index each value
When the code reaches the text value, a mismatch error is caused by this and everything grinds to a halt
By clicking on ‘Debug’ in the error pop-up, you will see the line of code which has the problem highlighted in yellow. By hovering your cursor over any instance of the variable ‘Coun’ within the code, you will be able to see the value of ‘Coun’ where the code has failed, which in this case is 5
Looking on the worksheet, you will see that the 5th cell down has the text value and this has caused the code to fail
You could change your code by putting in a condition that checks for a numeric value first before adding the cell value into the array
Sub TestMismatch()
Dim MyNumber(10) As Integer, Coun As Integer
Coun = 1
Do
If Coun = 11 Then Exit Do
If IsNumeric(Sheets("sheet1").Cells(Coun, 1).Value) Then
MyNumber(Coun) = Sheets("sheet1").Cells(Coun, 1).Value
Else
MyNumber(Coun) = 0
End If
Coun = Coun + 1
Loop
End Sub
The code uses the ‘IsNumeric’ function to test if the value is actually a number, and if it is then it enters it into the array. If it is not number then it enters the value of zero.
This ensures that the array index is kept in line with the cell row numbers in the spreadsheet.
You could also add code that copies the original error value and location details to an ‘Errors’ worksheet so that the user can see what they have done wrong when your code is run.
The numeric test uses the full code for the cell as well as the code to assign the value into the array. You could argue that this should be assigned to a variable so as not to keep repeating the same code, but the problem is that you would need to define the variable as a ‘Variant’ which is not the best thing to do.
You also need data validation on the worksheet and to password protect the worksheet. This will prevent the user inserting rows, and entering unexpected data.
Mismatch Error Caused by Calling a Function or Sub Routine Using Parameters
When a function is called, you usually pass parameters to the function using data types already defined by the function. The function may be one already defined in VBA, or it may be a User Defined function that you have built yourself. A sub routine can also sometimes require parameters
If you do not stick to the conventions of how the parameters are passed to the function, you will get a mismatch error
Sub CallFunction()
Dim Ret As Integer
Ret = MyFunction(3, "test")
End Sub
Function MyFunction(N As Integer, T As String) As String
MyFunction = T
End Function
There are several possibilities here to get a mismatch error
The return variable (Ret) is defined as an integer, but the function returns a string. As soon as you run the code, it will fail because the function returns a string, and this cannot go into an integer variable. Interestingly, running Debug on this code does not pick up this error.
If you put quote marks around the first parameter being passed (3), it is interpreted as a string, which does not match the definition of the first parameter in the function (integer)
If you make the second parameter in the function call into a numeric value, it will fail with a mismatch because the second parameter in the string is defined as a string (text)
Mismatch Error Caused by using Conversion Functions in VBA Incorrectly
There are a number of conversion functions that your can make use of in VBA to convert values to various data types. An example is ‘CInt’ which converts a string containing a number into an integer value.
If the string to be converted contains any alpha characters then you will get a mismatch error, even if the first part of the string contains numeric characters and the rest is alpha characters e.g. ‘123abc’
General Prevention of Mismatch Errors
We have seen in the examples above several ways of dealing with potential mismatch errors within your code, but there are a number of other ways, although they may not be the best options:
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Define your variables as Variant Type
A variant type is the default variable type in VBA. If you do not use a Dim statement for a variable and simply start using it in your code, then it is automatically given the type of Variant.
A Variant variable will accept any type of data, whether it is an integer, long integer, double precision number, boolean, or text value. This sounds like a wonderful idea, and you wonder why everyone does not just set all their variables to variant.
However, the variant data type has several downsides. Firstly, it takes up far more memory than other data types. If you define a very large array as variant, it will swallow up a huge amount of memory when the VBA code is running, and could easily cause performance issues
Secondly, it is slower in performance generally, than if you are using specific data types. For example, if you are making complex calculations using floating decimal point numbers, the calculations will be considerably slower if you store the numbers as variants, rather than double precision numbers
Using the variant type is considered sloppy programming, unless there is an absolute necessity for it.
Use the OnError Command to Handle Errors
The OnError command can be included in your code to deal with error trapping, so that if an error does ever occur the user sees a meaningful message instead of the standard VBA error pop-up
Sub ErrorTrap()
Dim MyNumber As Integer
On Error GoTo Err_Handler
MyNumber = "test"
Err_Handler:
MsgBox "The error " & Err.Description & " has occurred"
End Sub
This effectively prevents the error from stopping the smooth running of your code and allows the user to recover cleanly from the error situation.
The Err_Handler routine could show further information about the error and who to contact about it.
From a programming point of view, when you are using an error handling routine, it is quite difficult to locate the line of code the error is on. If you are stepping through the code using F8, as soon as the offending line of code is run, it jumps to the error handling routine, and you cannot check where it is going wrong.
A way around this is to set up a global constant that is True or False (Boolean) and use this to turn the error handling routine on or off using an ‘If’ statement. When you want to test the error all you have to do is set the global constant to False and the error handler will no longer operate.
Global Const ErrHandling = False
Sub ErrorTrap()
Dim MyNumber As Integer
If ErrHandling = True Then On Error GoTo Err_Handler
MyNumber = "test"
Err_Handler:
MsgBox "The error " & Err.Description & " has occurred"
End Sub
The one problem with this is that it allows the user to recover from the error, but the rest of the code within the sub routine does not get run, which may have enormous repercussions later on in the application
Using the earlier example of looping through a range of cells, the code would get to cell A5 and hit the mismatched error. The user would see a message box giving information on the error, but nothing from that cell onwards in the range would be processed.
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Use the OnError Command to Supress Errors
This uses the ‘On Error Resume Next’ command. This is very dangerous to include in your code as it prevents any subsequent errors being shown. This basically means that as your code is executing, if an error occurs in a line of code, execution will just move to the next available line without executing the error line, and carry on as normal.
This may sort out a potential error situation, but it will still affect every future error in the code. You may then think that your code is bug free, but in fact it is not and parts of your code are not doing what you think it ought to be doing.
There are situations where it is necessary to use this command, such as if you are deleting a file using the ‘Kill’ command (if the file is not present, there will be an error), but the error trapping should always be switched back on immediately after where the potential error could occur using:
On Error Goto 0
In the earlier example of looping through a range of cells, using ‘On Error Resume Next’, this would enable the loop to continue, but the cell causing the error would not be transferred into the array, and the array element for that particular index would hold a null value.
Converting the Data to a Data Type to Match the Declaration
You can use VBA functions to alter the data type of incoming data so that it matches the data type of the receiving variable.
You can do this when passing parameters to functions. For example, if you have a number that is held in a string variable and you want to pass it as a number to a function, you can use CInt
There are a number of these conversion functions that can be used, but here are the main ones:
CInt – converts a string that has a numeric value (below + or – 32,768) into an integer value. Be aware that this truncates any decimal points off
CLng – Converts a string that has a large numeric value into a long integer. Decimal points are truncated off.
CDbl – Converts a string holding a floating decimal point number into a double precision number. Includes decimal points
CDate – Converts a string that holds a date into a date variable. Partially depends on settings in the Windows Control Panel and your locale on how the date is interpreted
CStr – Converts a numeric or date value into a string
When converting from a string to a number or a date, the string must not contain anything other that numbers or a date. If alpha characters are present this will produce a mismatch error. Here is an example that will produce a mismatch error:
Sub Test()
MsgBox CInt("123abc")
End Sub
Testing Variables Within Your Code
You can test a variable to find out what data type it is before you assign it to a variable of a particular type.
For example, you could check a string to see if it is numeric by using the ‘IsNumeric’ function in VBA
MsgBox IsNumeric("123test")
This code will return False because although the string begins with numeric characters, it also contains text so it fails the test.
MsgBox IsNumeric("123")
This code will return True because it is all numeric characters
There are a number of functions in VBA to test for various data types, but these are the main ones:
IsNumeric – tests whether an expression is a number or not
IsDate – tests whether an expression is a date or not
IsNull – tests whether an expression is null or not. A null value can only be put into a variant object otherwise you will get an error ‘Invalid Use of Null’. A message box returns a null value if you are using it to ask a question, so the return variable has to be a variant. Bear in mind that any calculation using a null value will always return the result of null.
IsArray – tests whether the expression represents an array or not
IsEmpty – tests whether the expression is empty or not. Note that empty is not the same as null. A variable is empty when it is first defined but it is not a null value
Surprisingly enough, there is no function for IsText or IsString, which would be really useful
Objects and Mismatch Errors
If you are using objects such as a range or a sheet, you will get a mismatch error at compile time, not at run time, which gives you due warning that your code is not going to work
Sub TestRange()
Dim MyRange As Range, I As Long
Set MyRange = Range("A1:A2")
I = 10
x = UseMyRange(I)
End Sub
Function UseMyRange(R As Range)
End Function
This code has a function called ‘UseMyRange’ and a parameter passed across as a range object. However, the parameter being passed across is a Long Integer which does not match the data type.
When you run VBA code, it is immediately compiled, and you will see this error message:
The offending parameter will be highlighted with a blue background
Generally, if you make mistakes in VBA code using objects you will see this error message, rather than a type mismatch message: