Перенос текста в ячейке в excel python - Word и Excel - помощь в работе с программами

I have a Pandas dataframe that I am writing out to an XLSX using openpyxl. Many of the cells in the spreadsheet contain long sentences, and i want to set ‘wrap_text’ on all the contents of the sheet (i.e. every cell).

Is there a way to do this? I have seen openpyxl has an ‘Alignment’ option for ‘wrap_text’, but I cannot see how to apply this to all cells.

Edit:

Thanks to feedback, the following does the trick. Note — copy due to styles being immutable.

for row in ws.iter_rows():
    for cell in row:      
        cell.alignment =  cell.alignment.copy(wrapText=True)

asked Feb 14, 2017 at 0:34

DerRabeDerRabe

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I have been using openpyxl>=2.5.6. Let us say we want to wrap text for cell A1, then we can use the below code.

from openpyxl.styles import Alignment

ws['A1'].alignment = Alignment(wrap_text=True)

answered Sep 25, 2018 at 9:08

SuperNovaSuperNova

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Presumably, when you iterate through your cells, the idea would be to apply the format at that.

for row in ws.iter_rows():
    for cell in row:
        cell.style.alignment.wrap_text=True

There is also a fair amount more detail into how to use the wrap text style here
Writing multi-line strings into cells using openpyxl

Hope this helps.

answered Feb 14, 2017 at 18:07

Allan BAllan B

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import os
import openpyxl
from openpyxl.styles import Alignment, Font
from openpyxl.cell import Cell
#format cells with word wrap and top alignment    
for row in ws2.iter_rows():  
    for cell in row:      
        cell.alignment = Alignment(wrap_text=True,vertical='top')

answered Jun 3, 2020 at 13:32

Update alignment in openpyxl v3

Many of the answers set wrapText=True but clobber existing alignment options. This is no good.

Using openpyxl v3.0.4, I did the following:

import copy

for row in ws.iter_rows():
    for cell in row:      
        alignment = copy.copy(cell.alignment)
        alignment.wrapText=True
        cell.alignment = alignment

The original poster’s solution uses:

cell.alignment =  cell.alignment.copy(wrapText=True)

But this produced the following warning:

DeprecationWarning: Call to deprecated function copy (Use copy(obj) or cell.obj = cell.obj + other).
  cell.alignment =  cell.alignment.copy(wrapText=True)

answered Jul 28, 2020 at 18:49

Iterates all cells

  for rows in ws.iter_rows(min_row=1, min_col=1):
    for cell in rows:
      print('cell %s %s' % (cell.coordinate,cell.value))

* Tested with Python:3.4.2 — openpyxl:2.4.1 *

answered Feb 14, 2017 at 7:52

stovflstovfl

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В openpyxl вы можете установить свойство выравнивания wrap_text для переноса многострочных строк:

from openpyxl import Workbook

workbook = Workbook()
worksheet = workbook.worksheets[0]
worksheet.title = "Sheet1"

worksheet.cell('A1').style.alignment.wrap_text = True
worksheet.cell('A1').value = "Line 1nLine 2nLine 3"

workbook.save('wrap_text1.xlsx')

Это также возможно с помощью XlsxWriter.

Вот небольшой рабочий пример:

from xlsxwriter.workbook import Workbook

# Create an new Excel file and add a worksheet.
workbook = Workbook('wrap_text2.xlsx')
worksheet = workbook.add_worksheet()

# Widen the first column to make the text clearer.
worksheet.set_column('A:A', 20)

# Add a cell format with text wrap on.
cell_format = workbook.add_format({'text_wrap': True})

# Write a wrapped string to a cell.
worksheet.write('A1', "Line 1nLine 2nLine 3", cell_format)

workbook.close()

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Python:
Is there a way to write multi-line strings into an excel cell with just the xlwt module? (I saw answers suggesting use of openpyxl module)

The sheet.write() method ignores the n escape sequence. So, just xlwt, is it possible? Thanks in advance.

asked Sep 16, 2013 at 7:24

I found the answer in the python-excel Google Group. Using sheet.write() with the optional style argument, enabling word wrap for the cell, does the trick. Here is a minimum working example:

import xlwt
book = xlwt.Workbook()
sheet = book.add_sheet('Test')

# A1: no style, no wrap, despite newline
sheet.write(0, 0, 'HellonWorld')

# B1: with style, there is wrap
style = xlwt.XFStyle()
style.alignment.wrap = 1
sheet.write(0, 1, 'HellonWorld', style)
book.save('test.xls')

While in cell A1 shows HelloWorld without linebreak, cell B1 shows HellonWorld (i.e. with linebreak).

answered Sep 16, 2013 at 7:45

ojdoojdo

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If you don’t use XFStyle and instead easyxf it’s done like this:

import xlwt

style_head = xlwt.easyxf('alignment: wrap True')

row = 1
cell = 1
book = xlwt.Workbook(encoding='utf-8')
sheet = book.add_sheet()
sheet.write(row, cell, 'cell value', style_head)

answered Jul 4, 2019 at 12:30

Sam_sloSam_slo

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There are a few things you could try:

Windows handles new lines differently to Unix/Linux. While n (line feed) character is the standard Unix method and also used in Python, Windows requires a carriage return and line feed. You could therefore try replacing n with rn.
If this does not work then try replacing them with the ascii characters {chr(13) and chr(10)} inside a formula.
If this still doesn’t work then it may be worth trying this article which suggests a rather more long winded way of approaching the problem.

answered Sep 16, 2013 at 7:53

ChrisProsserChrisProsser

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Introduction¶

Normally styles apply to everything in an individual cell. However, rich text
allows formatting of parts of the text in a string. This section covers
adding rich-text formatting to worksheet cells. Rich-text formatting in
existing workbooks has to be enabled when loading them with the
rich_text=True parameter.

Rich Text objects can contain a mix of unformatted text and
TextBlock objects that contains an InlineFont style and a
the text which is to be formatted like this. The result is a
CellRichText object.

>>> from openpyxl.cell.text import InlineFont
>>> from openpyxl.cell.rich_text import TextBlock, CellRichText
>>> rich_string1 = CellRichText(
...    'This is a test ',
...    TextBlock(InlineFont(b=True), 'xxx'),
...   'yyy'
... )

InlineFont objects are virtually identical to the Font
objects, but use a different attribute name, rFont, for the name of the
font. Unfortunately, this is required by OOXML and cannot be avoided.

>>> inline_font = InlineFont(rFont='Calibri', # Font name
...                          sz=22,           # in 1/144 in. (1/2 point) units, must be integer
...                          charset=None,    # character set (0 to 255), less required with UTF-8
...                          family=None,     # Font family
...                          b=True,          # Bold (True/False)
...                          i=None,          # Italics (True/False)
...                          strike=None,     # strikethrough
...                          outline=None,
...                          shadow=None,
...                          condense=None,
...                          extend=None,
...                          color=None,
...                          u=None,
...                          vertAlign=None,
...                          scheme=None,
...                          )

Fortunately, if you already have a Font object, you can simply
initialize an InlineFont object with an existing Font
object:

>>> from openpyxl.cell.text import Font
>>> font = Font(name='Calibri',
...             size=11,
...             bold=False,
...             italic=False,
...             vertAlign=None,
...             underline='none',
...             strike=False,
...             color='00FF0000')
>>> inline_font = InlineFont(font)

You can create InlineFont objects on their own, and use them later.
This makes working with Rich Text cleaner and easier:

>>> big = InlineFont(sz="30.0")
>>> medium = InlineFont(sz="20.0")
>>> small = InlineFont(sz="10.0")
>>> bold = InlineFont(b=True)
>>> b = TextBlock
>>> rich_string2 = CellRichText(
...       b(big, 'M'),
...       b(medium, 'i'),
...       b(small, 'x'),
...       b(medium, 'e'),
...       b(big, 'd')
... )

For example:

>>> red = InlineFont(color='00FF0000')
>>> rich_string1 = CellRichText(['When the color ', TextBlock(red, 'red'), ' is used, you can expect ', TextBlock(red, 'danger')])

The CellRichText object is derived from list, and can be used as such.

Whitespace¶

CellRichText objects do not add whitespace between elements when rendering
them as strings or saving files.

>>> t = CellRichText()
>>> t.append('xx')
>>> t.append(TextBlock(red, "red"))

You can also cast it to a str to get only the text, without formatting.

Editing Rich Text¶

As editing large blocks of text with formatting can be tricky, the
as_list() method returns a list of strings to make indexing easy.

>>> l = rich_string1.as_list()
>>> l
['When the color ', 'red', ' is used, you can expect ', 'danger']
>>> l.index("danger")
3
>>> rich_string1[3].text = "fun"
>>> str(rich_string1)
'When the color red is used, you can expect fun'

Rich Text assignment to cells¶

Rich Text objects can be assigned directly to cells

>>> from openpyxl import Workbook
>>> wb = Workbook()
>>> ws = wb.active
>>> ws['A1'] = rich_string1
>>> ws['A2'] = 'Simple string'

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У меня есть фрейм данных Pandas, который я записываю в XLSX, используя openpyxl. Многие ячейки в электронной таблице содержат длинные предложения, и я хочу установить wrap_text для всего содержимого листа (то есть для каждой ячейки).

Есть ли способ сделать это? Я видел, что openpyxl имеет опцию ‘Alignment’ для ‘wrap_text’, но я не вижу, как применить это ко всем ячейкам.

Редактировать:

Благодаря обратной связи, следующее делает свое дело. Примечание — копирование из-за того, что стили неизменны.

for row in ws.iter_rows():
    for cell in row:      
        cell.alignment =  cell.alignment.copy(wrapText=True)

3 ответа

Лучший ответ

Предположительно, когда вы перебираете свои ячейки, идея заключается в том, чтобы применить формат при этом.

for row in ws.iter_rows():
    for cell in row:
        cell.style.alignment.wrap_text=True

Здесь также есть довольно много подробностей о том, как использовать стиль переноса текста здесь Запись многострочных строк в ячейки с использованием openpyxl

Надеюсь это поможет.

Community
23 Май 2017 в 12:34

Я использовал openpyxl> = 2.5.6. Допустим, мы хотим обернуть текст для ячейки A1, тогда мы можем использовать приведенный ниже код.

from openpyxl.styles import Alignment

ws['A1'].alignment = Alignment(wrap_text=True)

SuperNova
21 Окт 2019 в 06:10

Перебирает все ячейки

  for rows in ws.iter_rows(min_row=1, min_col=1):
    for cell in rows:
      print('cell %s %s' % (cell.coordinate,cell.value))

* Протестировано с Python: 3.4.2 — openpyxl: 2.4.1 *

stovfl
14 Фев 2017 в 09:27

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