I am trying to convert some VBA code to C#. I am new to C#. Currently I am trying to open an Excel file from a folder and if it does not exist then create it. I am trying something like the following. How can I make it work?
Excel.Application objexcel;
Excel.Workbook wbexcel;
bool wbexists;
Excel.Worksheet objsht;
Excel.Range objrange;
objexcel = new Excel.Application();
if (Directory("C:\csharp\error report1.xls") = "")
{
wbexcel.NewSheet();
}
else
{
wbexcel.Open("C:\csharp\error report1.xls");
objsht = ("sheet1");
}
objsht.Activate();
abatishchev
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asked Jan 21, 2009 at 11:25
4
You need to have installed Microsoft Visual Studio Tools for Office (VSTO).
VSTO can be selected in the Visual Studio installer under Workloads > Web & Cloud > Office/SharePoint Development.
After that create a generic .NET project and add a reference to Microsoft.Office.Interop.Excel
via ‘Add Reference… > Assemblies’ dialog.
Application excel = new Application();
Workbook wb = excel.Workbooks.Open(path);
Missing.Value
is a special reflection struct for unnecessary parameters replacement
In newer versions, the assembly reference required is called Microsoft Excel 16.0 Object Library
. If you do not have the latest version installed you might have Microsoft Excel 15.0 Object Library
, or an older version, but it is the same process to include.
answered Jan 21, 2009 at 15:07
abatishchevabatishchev
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13
FileInfo fi = new FileInfo("C:\test\report.xlsx");
if(fi.Exists)
{
System.Diagnostics.Process.Start(@"C:testreport.xlsx");
}
else
{
//file doesn't exist
}
answered Oct 18, 2011 at 21:49
MennanMennan
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4
private void btnChoose2_Click(object sender, EventArgs e)
{
OpenFileDialog openfileDialog1 = new OpenFileDialog();
if (openfileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
{
this.btnChoose2.Text = openfileDialog1.FileName;
String filename = DialogResult.ToString();
var excelApp = new Excel.Application();
excelApp.Visible = true;
excelApp.Workbooks.Open(btnChoose2.Text);
}
}
LarsTech
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answered Jan 28, 2014 at 17:45
FlaneFlane
1111 silver badge3 bronze badges
1
Imports
using Excel= Microsoft.Office.Interop.Excel;
using Microsoft.VisualStudio.Tools.Applications.Runtime;
Here is the code to open an excel sheet using C#.
Microsoft.Office.Interop.Excel.Application excel = new Microsoft.Office.Interop.Excel.Application();
Microsoft.Office.Interop.Excel.Workbook wbv = excel.Workbooks.Open("C:\YourExcelSheet.xlsx");
Microsoft.Office.Interop.Excel.Worksheet wx = excel.ActiveSheet as Microsoft.Office.Interop.Excel.Worksheet;
wbv.Close(true, Type.Missing, Type.Missing);
excel.Quit();
Here is a video mate on how to open an excel worksheet using C# https://www.youtube.com/watch?v=O5Dnv0tfGv4
answered Aug 20, 2016 at 0:39
0
For opening a file, try this:
objexcel.Workbooks.Open(@"C:YourPathYourExcelFile.xls",
missing, missing, missing, missing, missing, missing, missing,
missing, missing, missing, missing, missing,missing, missing);
You must supply those stupid looking ‘missing’ arguments. If you were writing the same code in VB.Net you wouldn’t have needed them, but you can’t avoid them in C#.
answered Jan 21, 2009 at 11:39
2
you should open like this
Excel.Application xlApp ;
Excel.Workbook xlWorkBook ;
Excel.Worksheet xlWorkSheet ;
object misValue = System.Reflection.Missing.Value;
xlApp = new Excel.ApplicationClass();
xlWorkBook = xlApp.Workbooks.Open("csharp.net-informations.xls", 0, true, 5, "", "", true, Microsoft.Office.Interop.Excel.XlPlatform.xlWindows, "t", false, false, 0, true, 1, 0);
xlWorkSheet = (Excel.Worksheet)xlWorkBook.Worksheets.get_Item(1);
source : http://csharp.net-informations.com/excel/csharp-open-excel.htm
ruden
answered Apr 17, 2013 at 6:23
0
It’s easier to help you if you say what’s wrong as well, or what fails when you run it.
But from a quick glance you’ve confused a few things.
The following doesn’t work because of a couple of issues.
if (Directory("C:\csharp\error report1.xls") = "")
What you are trying to do is creating a new Directory object that should point to a file and then check if there was any errors.
What you are actually doing is trying to call a function named Directory() and then assign a string to the result. This won’t work since 1/ you don’t have a function named Directory(string str) and you cannot assign to the result from a function (you can only assign a value to a variable).
What you should do (for this line at least) is the following
FileInfo fi = new FileInfo("C:\csharp\error report1.xls");
if(!fi.Exists)
{
// Create the xl file here
}
else
{
// Open file here
}
As to why the Excel code doesn’t work, you have to check the documentation for the Excel library which google should be able to provide for you.
answered Jan 21, 2009 at 14:57
Mats FredrikssonMats Fredriksson
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Microsoft.Office.Interop.Excel.Application excapp;
excapp = new Microsoft.Office.Interop.Excel.Application();
object misval=System.Reflection.Missing.Value;
Workbook wrkbuk = new Workbook();
Worksheet wrksht = new Worksheet();
wrkbuk = excapp.Workbooks._Open(@"C:Users......_template_v1.0.xlsx", misval, misval,
misval, misval, misval, misval, misval, misval, misval, misval, misval, misval);
wrksht = (Microsoft.Office.Interop.Excel.Worksheet)wrkbuk.Worksheets.get_Item(2);
RememberME
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answered Jul 15, 2011 at 10:50
Is this a commercial application or some hobbyist / open source software?
I’m asking this because in my experience, all free .NET Excel handling alternatives have serious problems, for different reasons. For hobbyist things, I usually end up porting jExcelApi from Java to C# and using it.
But if this is a commercial application, you would be better off by purchasing a third party library, like Aspose.Cells. Believe me, it totally worths it as it saves a lot of time and time ain’t free.
answered Jan 21, 2009 at 15:29
Tamas CzinegeTamas Czinege
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Code :
private void button1_Click(object sender, EventArgs e)
{
textBox1.Enabled=false;
OpenFileDialog ofd = new OpenFileDialog();
ofd.Filter = "Excell File |*.xlsx;*,xlsx";
if (ofd.ShowDialog() == DialogResult.OK)
{
string extn = Path.GetExtension(ofd.FileName);
if (extn.Equals(".xls") || extn.Equals(".xlsx"))
{
filename = ofd.FileName;
if (filename != "")
{
try
{
string excelfilename = Path.GetFileName(filename);
}
catch (Exception ew)
{
MessageBox.Show("Errror:" + ew.ToString());
}
}
}
}
answered Jan 12, 2015 at 6:54
For editing Excel files from within a C# application, I recently started using NPOI.
I’m very satisfied with it.
answered Apr 4, 2012 at 15:06
bvgheluwebvgheluwe
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- Remove From My Forums
-
Question
-
Hi,
I want to write a program to access cells in an excel file?
How can I do that?
Thanks
Answers
-
Try this code!
Microsoft.Office.Interop.Excel.Application app = new Microsoft.Office.Interop.Excel.Application(); Microsoft.Office.Interop.Excel.Workbook wb = app.Workbooks.Open("your excel file path", Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing); Worksheet sheet = (Worksheet)wb.Sheets["Sheet name to read"]; Range excelRange = sheet.UsedRange; foreach (Microsoft.Office.Interop.Excel.Range row in excelRange.Rows) { int rowNumber = row.Row; string[] A4D4 = GetRange("A" + rowNumber + ":F" + rowNumber + "", sheet); } public string[] GetRange(string range, Worksheet excelWorksheet) { Microsoft.Office.Interop.Excel.Range workingRangeCells = excelWorksheet.get_Range(range, Type.Missing); //workingRangeCells.Select(); System.Array array = (System.Array)workingRangeCells.Cells.Value2; string[] arrayS = this.ConvertToStringArray(array); return arrayS; }
-
Edited by
Monday, September 5, 2011 6:40 AM
-
Marked as answer by
Martin_Xie
Monday, September 19, 2011 11:49 AM
-
Edited by
-
Hi DarkSeeker,
Try this:
static void Main(string[] args) { IWorkbook workbook = Factory.GetWorkbook(@"C:tmpMyWorkbook.xls"); IWorksheet worksheet = workbook.Worksheets[0]; IRange a1 = worksheet.Cells["A1"]; object rawValue = a1.Value; string formattedText = a1.Text; Console.WriteLine("rawValue={0} formattedText={1}", rawValue, formattedText); }
Regards, http://shwetamannjain.blogspot.com
-
Marked as answer by
Martin_Xie
Monday, September 19, 2011 11:50 AM
-
Marked as answer by
-
“I
want to write a program to access cells in an excel file?”Thanks all for your great help and suggestions.
Hi DarkSeeker,
Welcome to MSDN Forum.
Usually, there are 2 approaches to access Office Excel files in .Net.
1.
COM Interop approach as the above said.FAQ: How do I use Excel Automation in .NET
http://social.msdn.microsoft.com/Forums/en-US/vbgeneral/thread/df02c6d2-e1b5-4731-bb04-2674aed789de
Add Reference to COM component “Microsoft Excel Object Library” into your project.
Code sample: Get/Set cell value in Excel Spreadsheet.
using Microsoft.Office.Interop.Excel;
object oExcel
= new Excel.Application;object oBook
= oExcel.Workbooks.Open(«C:\Book1.xls»);
object oSheet =
oBook.Worksheets(1);
// e.g. Read value in A2 cell
string cellValue
= oSheet.Range(«A2»).Value;
// e.g. Change value in A2 cell
oSheet.Range(«A2»).Value
= «»;
oBook.SaveAs(«C:\Book1.xls»,
true);
oExcel.Quit();2. OleDb Data Provider approach
Retrieve Excel Sheet data and bind into DataGridView control, and then access particular cells via DataGridView.
using System.Data;
using System.Data.OleDb;
OleDbConnection conn = new
OleDb.OleDbConnection((«provider=Microsoft.Jet.OLEDB.4.0; »
+ («data source=C:\myData.xls; »
+ «Extended Properties=Excel 8.0;»)));
// Select the data from Sheet1 of the workbook.
OleDbDataAdapter ada = new
OleDbDataAdapter(«select * from Sheet1$]», conn);
DataSet ds = new
DataSet();
ada.Fill(ds);
dataGridView1.DataSource
= ds.Tables[0].DefaultView;
conn.Close();// Access particular cells on DataGridView.
DataGridView1(RowIndex, ColumnIndex)
DataGridView1.Rows(RowIndex).Cells(ColumnIndex)
Martin Xie [MSFT]
MSDN Community Support | Feedback to us
Get or Request Code Sample from Microsoft
Please remember to mark the replies as answers if they help and unmark them if they provide no help.-
Proposed as answer by
Carmelo La Monica
Tuesday, September 6, 2011 5:54 AM -
Marked as answer by
Martin_Xie
Monday, September 19, 2011 11:48 AM
-
Proposed as answer by
Table of Contents
- Background
- Prerequisites
- Source Code
Background
A few days ago we got a requirement to read Excel files and store those values in the SQL server database. So in this example, we’re going to show how to get the basic four import data such as Excel Work Book
Name, Worksheet Count in that Workbook, Name of the First Worksheet, and finally the value of the first cell in that worksheet.
Prerequisites
Kindly ensure you add the following DLL as shown in the below screenshot,
Namespace
using Excel = Microsoft.Office.Interop.Excel;
Source Code
C# Code
- protected void BtnGetExcelFileDetails_Click(object sender, EventArgs e)
- {
- try
- {
- Excel.Application oExcel = new Excel.Application();
- string filepath = @ «D:TPMSUploaded_BoqRaveena_boq_From_Db.xlsx»;
- Excel.Workbook WB = oExcel.Workbooks.Open(filepath);
- string ExcelWorkbookname = WB.Name;
- int worksheetcount = WB.Worksheets.Count;
- Excel.Worksheet wks = (Excel.Worksheet) WB.Worksheets[1];
- string firstworksheetname = wks.Name;
- var firstcellvalue = ((Excel.Range) wks.Cells[1, 1]).Value;
- } catch (Exception ex)
- {
- string error = ex.Message;
- }
- }
Hope the above information was useful.
Все привет, в этой статье опишу исчерпывающие примеры работы с excel на языке C#.
Для начала работы нам необходимо подключить библиотеку COM как на рисунке ниже:
Для этого добавляем ссылку в проект, надеюсь вы знаете как это делается) Выбираем пункт COM ищем библиотеку Microsoft Excel 16.0 Object Library ставим галочку и жмем Ок.
Далее нам не обходимо для сокращения записи и удобства создать алиас.
using Excel = Microsoft.Office.Interop.Excel; |
Теперь нам нужно объявить объект Excel задать параметры и приступать к работе.
//Объявляем приложение Excel.Application app = new Excel.Application { //Отобразить Excel Visible = true, //Количество листов в рабочей книге SheetsInNewWorkbook = 2 }; //Добавить рабочую книгу Excel.Workbook workBook = app.Workbooks.Add(Type.Missing); //Отключить отображение окон с сообщениями app.DisplayAlerts = false; //Получаем первый лист документа (счет начинается с 1) Excel.Worksheet sheet = (Excel.Worksheet)app.Worksheets.get_Item(1); //Название листа (вкладки снизу) sheet.Name = «Имя должно быть не больше 32сим»; |
Пример заполнения ячейки:
//Пример заполнения ячеек №1 for (int i = 1; i <= 9; i++) { for (int j = 1; j < 9; j++) sheet.Cells[i, j] = String.Format(«nookery {0} {1}», i, j); } //Пример №2 sheet.Range[«A1»].Value = «Пример №2»; //Пример №3 sheet.get_Range(«A2»).Value2 = «Пример №3»; |
Захват диапазона ячеек:
//Захватываем диапазон ячеек Вариант №1 Excel.Range r1 = sheet.Cells[1, 1]; Excel.Range r2 = sheet.Cells[9, 9]; Excel.Range range1 = sheet.get_Range(r1, r2); //Захватываем диапазон ячеек Вариант №2 Excel.Range range2 = sheet.get_Range(«A1»,«H9» ); |
Оформление, шрифт, размер, цвет, толщина.
//Шрифт для диапазона range.Cells.Font.Name = «Tahoma»; range2.Cells.Font.Name = «Times New Roman»; //Размер шрифта для диапазона range.Cells.Font.Size = 10; //Жирный текст range.Font.Bold = true; //Цвет текста range.Font.Color = ColorTranslator.ToOle(Color.Blue); |
Объединение ячеек в одну
//Объединение ячеек с F2 по K2 Excel.Range range3 = sheet.get_Range(«F2», «K2»); range3.Merge(Type.Missing); |
Изменяем размеры ячеек по ширине и высоте
//увеличиваем размер по ширине диапазон ячеек Excel.Range range2 = sheet.get_Range(«D1», «S1»); range2.EntireColumn.ColumnWidth = 10; //увеличиваем размер по высоте диапазон ячеек Excel.Range rowHeight = sheet.get_Range(«A4», «S4»); rowHeight.EntireRow.RowHeight = 50;range.EntireColumn.AutoFit();range.EntireColumn.AutoFit(); //авторазмер |
Создаем обводку диапазона ячеек
Excel.Range r1 = sheet.Cells[countRow, 2]; Excel.Range r2 = sheet.Cells[countRow, 19]; Excel.Range rangeColor = sheet.get_Range(r1, r2); rangeColor.Borders.Color = ColorTranslator.ToOle(Color.Black); |
Производим выравнивания содержимого диапазона ячеек.
Excel.Range r = sheet.get_Range(«A1», «S40»); //Оформления r.Font.Name = «Calibri»; r.Cells.Font.Size = 10; r.VerticalAlignment = Excel.XlVAlign.xlVAlignCenter; r.HorizontalAlignment = Excel.XlHAlign.xlHAlignCenter; |
Примеры вычисления формул, все вставки формул были скопированы из самой Excel без изменений. Позиция ячейки взята из счетчика переменно и подставлен к букве ячейки
sheet.Cells[countRow, countColumn] = $«=G{countRow}-F{countRow}»; sheet.Cells[countRow, countColumn].FormulaLocal = $«=ЕСЛИ((H{countRow}*O{countRow})+(I{countRow}*P{countRow})/100<=0;J{countRow}*O{countRow}/100;((H{countRow}*O{countRow})+(I{countRow}*P{countRow}))/100)»; sheet.Cells[countRow, countColumn] = $«=K{countRow}+N{countRow}-R{countRow}»; sheet.Cells[33, 22].FormulaLocal = «=СУММ(V3:V32)»; |
Добавляем разрыв страницы.
//Ячейка, с которой будет разрыв Excel.Range razr = sheet.Cells[n, m] as Excel.Range; //Добавить горизонтальный разрыв (sheet — текущий лист) sheet.HPageBreaks.Add(razr); //VPageBreaks — Добавить вертикальный разрыв |
Как открыть фаил Excel
app.Workbooks.Open(@»C:UsersUserDocumentsExcel.xlsx», Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing); |
Сохраняем документ Excel
app.Application.ActiveWorkbook.SaveAs(«MyFile.xlsx», Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Excel.XlSaveAsAccessMode.xlNoChange, Type.Missing, Type.Missing, Type.Missing, Type.Missing, Type.Missing); |
Завершение работы с объектом Excel.Application
app.Quit(); System.Runtime.InteropServices.Marshal.ReleaseComObject(app); |
Пример как выбрать фаил и загрузив его и узнать количество заполненных строк и колонок в одном конкретном листе по имени.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 |
//поиск файла Excel OpenFileDialog ofd = new OpenFileDialog(); ofd.Multiselect =false; ofd.DefaultExt = «*.xls;*.xlsx»; ofd.Filter = «Microsoft Excel (*.xls*)|*.xls*»; ofd.Title = «Выберите документ Excel»; if (ofd.ShowDialog() != DialogResult.OK) { MessageBox.Show(«Вы не выбрали файл для открытия», «Внимание», MessageBoxButtons.OK, MessageBoxIcon.Information); return; } string xlFileName = ofd.FileName; //имя нашего Excel файла //рабоата с Excel Excel.Range Rng; Excel.Workbook xlWB; Excel.Worksheet xlSht; int iLastRow, iLastCol; Excel.Application xlApp = new Excel.Application(); //создаём приложение Excel xlWB = xlApp.Workbooks.Open(xlFileName); //открываем наш файл xlSht = xlWB.Worksheets[«Лист1»]; //или так xlSht = xlWB.ActiveSheet //активный лист iLastRow = xlSht.Cells[xlSht.Rows.Count, «A»].End[Excel.XlDirection.xlUp].Row; //последняя заполненная строка в столбце А iLastCol = xlSht.Cells[1, xlSht.Columns.Count].End[Excel.XlDirection.xlToLeft].Column; //последний заполненный столбец в 1-й строке |
Получаем список всех загруженных книг «листов» из файла
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 |
//поиск файла Excel OpenFileDialog ofd = new OpenFileDialog(); ofd.Multiselect = false; ofd.DefaultExt = «*.xls;*.xlsx»; ofd.Filter = «Microsoft Excel (*.xls*)|*.xls*»; ofd.Title = «Выберите документ Excel»; if (ofd.ShowDialog() != DialogResult.OK) { MessageBox.Show(«Вы не выбрали файл для открытия», «Внимание», MessageBoxButtons.OK, MessageBoxIcon.Information); return; } string xlFileName = ofd.FileName; //имя нашего Excel файла Excel.Workbook xlWB = ex.Workbooks.Open(xlFileName); ///загружаем список всех книг foreach (object item in xlWB.Sheets) { Excel.Worksheet sheet = (Excel.Worksheet)item; } |
Blog / Import Excel to Datagridview using C#
In this tutorial, I will show you how to import an excel file to a DataGridview using C#. We are going to be using Microsoft.Office.interop.Excel namespace in this project. There are many ways to read an excel file in C#, but this is the easy way I found for beginners like me. Just follow the steps below.
Before we start, make sure that you have Visual Studio installed on your machine. If not, you can visit this download link. You can download the community version for free.
Let’s Start:
- First, Create a new Windows forma project. Navigate to File. Choose New option. Select Project.
2. From the New Project window. Name your project in any way you want. In my case, I name my project Upload_Data_From_Excel. Proceed on clicking the “Ok” button. See the image below.
3. Add controls from the toolbox. What we need is a Form, buttons, and OpenFileDialog.
- Form
- Button -> for the upload click event.
- OpenFileDialog -> for browsing files.
- DataGridview ->for viewing of data
Below image is the UI I created. This will help you visualize and understand the next step.
- For clarity and easy navigating, we will rename our button. Click the button you added to your form and go to its property from the solution explorer and change the value. In my case, I name it as btn_Upload.
5. Now navigate to your solution explorer and right-click on Reference, choose Add Reference, and then add Microsoft.Office.Interop.Excel.
6. From the reference manager window, expand Assemblies, and click Extensions from the left pane and search for Microsoft.Office.Interop.Excel from the middle pane.
7. Verify if the reference is added. Go to your project solution explorer. Expand Reference, then look for Microsoft.Office.Interop.Excel.
8. After we verify and successfully added Microsoft.Office.Interop.Excel. Open your form design and double click on the btn_Upload button to add button click event.
9. Copy and paste the code below to your btn_Upload Click Event.
string file = ""; //variable for the Excel File Location
DataTable dt = new DataTable(); //container for our excel data
DataRow row;
DialogResult result = openFileDialog1.ShowDialog(); // Show the dialog.
if (result == DialogResult.OK) // Check if Result == "OK".
{
file = openFileDialog1.FileName; //get the filename with the location of the file
try {
//Create Object for Microsoft.Office.Interop.Excel that will be use to read excel file
Microsoft.Office.Interop.Excel.Application excelApp = new Microsoft.Office.Interop.Excel.Application();
Microsoft.Office.Interop.Excel.Workbook excelWorkbook = excelApp.Workbooks.Open(file);
Microsoft.Office.Interop.Excel._Worksheet excelWorksheet = excelWorkbook.Sheets[1];
Microsoft.Office.Interop.Excel.Range excelRange = excelWorksheet.UsedRange;
int rowCount = excelRange.Rows.Count; //get row count of excel data
int colCount = excelRange.Columns.Count; // get column count of excel data
//Get the first Column of excel file which is the Column Name
for (int i = 1; i <= rowCount; i++) {
for (int j = 1; j <= colCount; j++) {
dt.Columns.Add(excelRange.Cells[i, j].Value2.ToString());
}
break;
}
//Get Row Data of Excel
int rowCounter; //This variable is used for row index number
for (int i = 2; i <= rowCount; i++) //Loop for available row of excel data
{
row = dt.NewRow(); //assign new row to DataTable
rowCounter = 0;
for (int j = 1; j <= colCount; j++) //Loop for available column of excel data
{
//check if cell is empty
if (excelRange.Cells[i, j] != null && excelRange.Cells[i, j].Value2 != null) {
row[rowCounter] = excelRange.Cells[i, j].Value2.ToString();
}
else {
row[i] = "";
}
rowCounter++;
}
dt.Rows.Add(row); //add row to DataTable
}
dataGridView1.DataSource = dt; //assign DataTable as Datasource for DataGridview
//close and clean excel process
GC.Collect();
GC.WaitForPendingFinalizers();
Marshal.ReleaseComObject(excelRange);
Marshal.ReleaseComObject(excelWorksheet);
//quit apps
excelWorkbook.Close();
Marshal.ReleaseComObject(excelWorkbook);
excelApp.Quit();
Marshal.ReleaseComObject(excelApp);
}
catch(Exception ex) {
MessageBox.Show(ex.Message);
}
- Now you are ready to run your project and test if no error occurs. Run your application by pressing ctrl + f5 without debugging or f5 for debugging mode.
- Click Upload button to upload.
- Then select your excel file. See the image below.
This is how to Import Excel to Datagridview using C# code. Hopes this helps.
Final output:
Excel File:
Project Output:
Full Code:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.IO;
using System.Linq;
using System.Runtime.InteropServices;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
namespace Upload_Data_From_Excel
{
public partial class Upload_Data_Frm_EXCEL : Form
{
public Upload_Data_Frm_EXCEL()
{
InitializeComponent();
}
private void btn_upload_Click(object sender, EventArgs e)
{
string file = ""; //variable for the Excel File Location
DataTable dt = new DataTable(); //container for our excel data
DataRow row;
DialogResult result = openFileDialog1.ShowDialog(); // Show the dialog.
if (result == DialogResult.OK) // Check if Result == "OK".
{
file = openFileDialog1.FileName; //get the filename with the location of the file
try
{
//Create Object for Microsoft.Office.Interop.Excel that will be use to read excel file
Microsoft.Office.Interop.Excel.Application excelApp = new Microsoft.Office.Interop.Excel.Application();
Microsoft.Office.Interop.Excel.Workbook excelWorkbook = excelApp.Workbooks.Open(file);
Microsoft.Office.Interop.Excel._Worksheet excelWorksheet = excelWorkbook.Sheets[1];
Microsoft.Office.Interop.Excel.Range excelRange = excelWorksheet.UsedRange;
int rowCount = excelRange.Rows.Count; //get row count of excel data
int colCount = excelRange.Columns.Count; // get column count of excel data
//Get the first Column of excel file which is the Column Name
for (int i = 1; i <= rowCount; i++)
{
for (int j = 1; j <= colCount; j++)
{
dt.Columns.Add(excelRange.Cells[i, j].Value2.ToString());
}
break;
}
//Get Row Data of Excel
int rowCounter; //This variable is used for row index number
for (int i = 2; i <= rowCount; i++) //Loop for available row of excel data
{
row = dt.NewRow(); //assign new row to DataTable
rowCounter = 0;
for (int j = 1; j <= colCount; j++) //Loop for available column of excel data
{
//check if cell is empty
if (excelRange.Cells[i, j] != null && excelRange.Cells[i, j].Value2 != null)
{
row[rowCounter] = excelRange.Cells[i, j].Value2.ToString();
}
else
{
row[i] = "";
}
rowCounter++;
}
dt.Rows.Add(row); //add row to DataTable
}
dataGridView1.DataSource = dt; //assign DataTable as Datasource for DataGridview
//Close and Clean excel process
GC.Collect();
GC.WaitForPendingFinalizers();
Marshal.ReleaseComObject(excelRange);
Marshal.ReleaseComObject(excelWorksheet);
excelWorkbook.Close();
Marshal.ReleaseComObject(excelWorkbook);
//quit
excelApp.Quit();
Marshal.ReleaseComObject(excelApp);
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
}
}
}
}
Thank you for reading! Happy Coding!!
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