If found in list excel

Value exists in a range

Summary

To test if a value exists in a range of cells, you can use a simple formula based on the COUNTIF function and the IF function. In the example shown, the formula in F5, copied down, is:

where data is the named range B5:B16. As the formula is copied down it returns «Yes» if the value in column E exists in B5:B16 and «No» if not.

Generic formula

Explanation

In this example, the goal is to use a formula to check if a specific value exists in a range. The easiest way to do this is to use the COUNTIF function to count occurences of a value in a range, then use the count to create a final result.

COUNTIF function

The COUNTIF function counts cells that meet supplied criteria. The generic syntax looks like this:

Range is the range of cells to test, and criteria is a condition that should be tested. COUNTIF returns the number of cells in range that meet the condition defined by criteria. If no cells meet criteria, COUNTIF returns zero. In the example shown, we can use COUNTIF to count the values we are looking for like this

Once the named range data (B5:B16) and cell E5 have been evaluated, we have:

COUNTIF returns 1 because «Blue» occurs in the range B5:B16 once. Next, we use the greater than operator (>) to run a simple test to force a TRUE or FALSE result:

By itself, the formula above will return TRUE or FALSE. The last part of the problem is to return a «Yes» or «No» result. To handle this, we nest the formula above into the IF function like this:

This is the formula shown in the worksheet above. As the formula is copied down, COUNTIF returns a count of the value in column E. If the count is greater than zero, the IF function returns «Yes». If the count is zero, IF returns «No».

Slightly abbreviated

It is possible to shorten this formula slightly and get the same result like this:

Here, we have remove the «>0» test. Instead, we simply return the count to IF as the logical_test. This works because Excel will treat any non-zero number as TRUE when the number is evaluated as a Boolean.

Testing for a partial match

To test a range to see if it contains a substring (a partial match), you can add a wildcard to the formula. For example, if you have a value to look for in cell C1, and you want to check the range A1:A100 for partial matches, you can configure COUNTIF to look for the value in C1 anywhere in a cell by concatenating asterisks on both sides:

The asterisk (*) is a wildcard for one or more characters. By concatenating asterisks before and after the value in C1, the formula will count the text in C1 anywhere it appears in each cell of the range. To return «Yes» or «No», nest the formula inside the IF function as above.

An alternative formula using MATCH

As an alternative, you can use a formula that uses the MATCH function with the ISNUMBER function instead of COUNTIF:

The MATCH function returns the position of a match (as a number) if found, and #N/A if not found. By wrapping MATCH inside ISNUMBER, the final result will be TRUE when MATCH finds a match and FALSE when MATCH returns #N/A.

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How do I use a nested IF(AND) in an Excel array formula?

How do I get a nested ‘AND’ to work inside ‘IF’ in an array formula?

I reduced my problem to the following example: Note: the above image has been updated to included the array formula curly braces

At the top right, we have the search criteria in L3 («color») and L4 («shape»). At the left, column D contains working match formulas for both color and shape in the list of items. The first table shows the match formula working properly without using an array formula.

The second table shows an array formula that matches the color.

The third table shows an array formula that matches the shape.

On the right is my attempt to use both criteria in an array formula, by combining them with AND.

IF the value in the color column matches the color criteria (L3) and the value in the shape column matches the shape criteria (L4), then I want to see «MATCH!».

I did find a workaround: concatenate the values and criteria, and then match them inside a single IF. I feel like there should be a Better Way. like if AND worked as expected!

Note: Many of the answers below work correctly but not as array formulas, which is specifically what this question is about. I looked at my original question and realized I forgot to show the curly braces in the array formula examples. I have fixed the image to show them. Sorry for the confusion.

The key to answering these questions is to write something that works as an array formula, which is entered by pressing CTRL+SHIFT+ENTER after typing the formula into a cell. Excel will automaically add the curly braces to indicate that it’s an array formula.

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Excel — Find a value in an array and return the contents of the corresponding column

I am trying to find a value within an array and then return the value in a specific row in the corresponding column.

In the example below, I need to know which bay the Chevrolet is in:

I am looking for Chevrolet in the array C2:E5. Once it determines that the Chevrolet is in Column D, I need for it to return the value in D1. If it was in column E, I need it to return the value in E1.

Any help would be greatly appreciated. Thank you so much in advance.

4 Answers 4

Try this Array Formula:

or if you are sure that each column contains exactly what’s being searched it can be written like this:

Enter formula in any cell by pressing Ctrl + Shitf + Enter .

How does it work?
Our ultimate goal is to find the Column that contains the match:

• First we did the search for the match using this formula: SEARCH(A1,$C$1:$E$5) . It just checks if any of the entries matched A1. Actually, it can be simplified to $C$1:$E$5=A1 but I’m not sure if all entries in each column match exactly what’s in A1.
• That formula will produce an array of values when entered as array formula. Something like: . The result will be array of number(s) and error (if non was found). But we don’t want that, else we will be returning error everytime.
• We then use IF(NOT(ISERROR(SEARCH(A1,$C$1:$E$5))),COLUMN($A:$C),99^99) . This formula returns the Column Number if there is a match and a relatively huge number 99^99 otherwise. Result would be: <99^99, 99^99, 99^99, 2, . 99^99>.
• And we are close to what we need since we already have an array of Column and huge number. We just use SMALL to return the smallest number which in my opinion is the lowest Column Number where a match is found. So SMALL(IF(NOT(ISERROR(SEARCH(A1,$C$1:$E$5))),COLUMN($A:$C),99^99),1) would return 2. Which is the column where Chevrolet is referenced at $C$1:$E$1.
• Since we already have the column number we simply use INDEX Function which is: INDEX($C$1:$E$5,1,2) .

Note: 99^99 can be any relatively large number. Not necessarily 99^99 . Actual 16385(max column number in Excel 2007 and up + 1) can be used.

Result:

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Excel if found in array

This article demonstrates several ways to check if a cell contains any value based on a list. The first example shows how to check if any of the values in the list is in the cell.

The remaining examples show formulas that also return the matching values. You may need different formulas based on the Excel version you are using.

Read this article If cell equals value from list to match the entire cell to any value from a list. To match a single cell to a single value read this: If cell contains text

To check if a cell contains all values in the list read this: If cell contains multiple values

What’s on this page

1. Check if the cell contains any value in the list

The image above shows an array formula in cell C3 that checks if cell B3 contains at least one of the values in List (E3:E7), it returns «Yes» if any of the values are found in column B and returns nothing if the cell contains none of the values.

For example, cell B3 contains XBF which is found in cell E7. Cell B4 contains text ZDS found in cell E6. Cell C5 contains no values in the list.

You need to enter this formula as an array formula if you are not an Excel 365 subscriber. There is another formula below that doesn’t need to be entered as an array formula, however, it is slightly larger and more complicated.

1. Type formula in cell C3.
2. Press and hold CTRL + SHIFT simultaneously.
3. Press Enter once.
4. Release all keys.

Excel adds curly brackets to the formula automatically if you successfully entered the array formula. Don’t enter the curly brackets yourself.

1.1 Explaining formula in cell C3

Step 1 — Check if the cell contains any of the values in the list

The COUNTIF function lets you count cells based on a condition, however, it also allows you to count cells based on multiple conditions if you use a cell range instead of a cell.

The criteria argument utilizes a beginning and ending asterisk in order to match a text string and not the entire cell value, asterisks are one of two wildcard characters that you are allowed to use.

The ampersands concatenate the asterisks to cell range E3:E7.

and returns this array

which tells us that the last value in the list is found in cell B3.

Step 2 — Return TRUE if at least one value is 1

The OR function returns TRUE if at least one of the values in the array is TRUE, the numerical equivalent to TRUE is 1.

Step 3 — Return Yes or nothing

The IF function then returns «Yes» if the logical test evaluates to TRUE and nothing if the logical test returns FALSE.

returns «Yes» in cell B3.

Regular formula

The following formula is quite similar to the formula above except that it is a regular formula and it has an additional INDEX function.

Get the Excel file

2. Display matches if the cell contains text from a list

The image above demonstrates a formula that checks if a cell contains a value in the list and then returns that value. If multiple values match then all matching values in the list are displayed.

For example, cell B3 contains «ZDS, YNO, XBF» and cell range E3:E7 has two values that match, «ZDS» and «XBF».

Formula in cell C3:

The TEXTJOIN function is available for Office 2019 and Office 365 subscribers. You will get a #NAME error if your Excel version is missing this function. Office 2019 users may need to enter this formula as an array formula.

The next formula works with most Excel versions.

Array formula in cell C3:

However, it only returns the first match. There is another formula below that returns all matching values, check it out.

2.1 Explaining formula in cell C3

Step 1 — Count cells containing text strings

The COUNTIF function lets you count cells based on a condition, we are going to use multiple conditions. I am going to use asterisks to make the COUNTIF function check for a partial match.

The asterisk is one of two wild card characters that you can use, it matches 0 (zero) to any number of any characters.

This array contains as many values as there values in the list, the position of each value in the array matches the position of the value in the list. This means that we can tell from the array that the first value and the last value is found in cell B3.

Step 2 — Return the actual value

The IF function returns one value if the logical test is TRUE and another value if the logical test is FALSE.

IF(logical_test, [value_if_true], [value_if_false])

This allows us to create an array containing values that exists in cell B3.

Step 3 — Concatenate values in array

The TEXTJOIN function allows you to combine text strings from multiple cell ranges and also use delimiting characters if you want.

TEXTJOIN(«, «, TRUE, IF(COUNTIF(B3, «*»&$E$3:$E$7&»*»), $E$3:$E$7, «»))

and returns text strings ZDS, XBF.

3. Display matches if cell contains text from a list (Earlier Excel versions)

The image above demonstrates a formula that returns multiple matches if the cell contains values from a list. This array formula works with most Excel versions.

Array formula in cell C3:

Copy cell C3 and paste to cell range C3:E15.

3.1 Explaining formula in cell C3

Step 1 — Identify matching values in cell

The COUNTIF function lets you count cells based on a condition, we are going to use a cell range instead. This will return an array of values.

Step 2 — Calculate relative positions of matching values

The IF function returns one value if the logical test is TRUE and another value if the logical test is FALSE.

IF(logical_test, [value_if_true], [value_if_false])

This allows us to create an array containing values representing row numbers.

I am going to use the SMALL function to be able to extract one value in each cell in the next step.

SMALL(IF(COUNTIF($B3, «*»&$G$3:$G$7&»*»), MATCH(ROW($G$3:$G$7), ROW($G$3:$G$7)), «»), COLUMNS($A$1:A1)))

The COLUMNS function calculates the number of columns in a cell range, however, the cell reference in our formula grows when you copy the cell and paste to adjacent cells to the right.

Step 4 — Return value based on row number

The INDEX function returns a value from a cell range or array, you specify which value based on a row and column number. Both the [row_num] and [column_num] are optional.

INDEX($G$3:$G$7, SMALL(IF(COUNTIF($B3, «*»&$G$3:$G$7&»*»), MATCH(ROW($G$3:$G$7), ROW($G$3:$G$7)), «»), COLUMNS($A$1:A1)))

and returns «ZDS» in cell C3.

Step 5 — Remove error values

The IFERROR function lets you catch most errors in Excel formulas except #SPILL! errors. Be careful when using the IFERROR function, it may make it much harder spotting formula errors.

There are two arguments in the IFERROR function. The value argument is returned if it is not evaluating to an error. The value_if_error argument is returned if the value argument returns an error.

IFERROR(INDEX($G$3:$G$7, SMALL(IF(COUNTIF($B3, «*»&$G$3:$G$7&»*»), MATCH(ROW($G$3:$G$7), ROW($G$3:$G$7)), «»), COLUMNS($A$1:A1))), «»)

4. Filter delimited values not in the list (Excel 365)

The formula in cell C3 lists values in cell B3 that are not in the List specified in cell range E3:E7. The formula returns #CALC! error if all values are in the list, see cell C14 as an example.

Excel 365 dynamic array formula in cell C3:

4.1 Explaining formula

Step 1 — Split values with a delimiting character

The TEXTSPLIT function splits a string into an array based on delimiting values.

Function syntax: TEXTSPLIT(Input_Text, col_delimiter, [row_delimiter], [Ignore_Empty])

TEXTSPLIT(«ZDS, VTO, XBF»,,»,»)

Step 2 — Remove leading and trailing spaces

The TRIM function deletes all blanks or space characters except single blanks between words in a cell value.

Function syntax: TRIM(text)

Step 3 — Check if values are in list

The COUNTIF function calculates the number of cells that is equal to a condition.

Function syntax: COUNTIF(range, criteria)

These numbers indicate if a value is found in the list, zero means not in the list and 1 or higher means that the value is in the list at least once.

The number’s position corresponds to the position of the values. <1; 0; 1>— <«ZDS»; «VTO»; «XBF»>meaning «ZDS» and «XBF» are in the list and «VTO» not.

Step 4 — Not

The NOT function returns the boolean opposite to the given argument.

Function syntax: NOT(logical)

0 (zero) is equivalent to FALSE. The boolean opposite is TRUE.

Any other number than 0 (zero) is equivalent to TRUE. The boolean opposite is FALSE.

Step 5 — Filter

The FILTER function extracts values/rows based on a condition or criteria.

Function syntax: FILTER(array, include, [if_empty])

Step 6 — Join

The TEXTJOIN function combines text strings from multiple cell ranges.

Function syntax: TEXTJOIN(delimiter, ignore_empty, text1, [text2], . )

Step 7 — Shorten the formula

The LET function lets you name intermediate calculation results which can shorten formulas considerably and improve performance.

Function syntax: LET(name1, name_value1, calculation_or_name2, [name_value2, calculation_or_name3. ])

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48 Responses to “If cell contains text from list”

Great post, very helpful. thanks.

How would you show the actual match rather than just «Yes»?

Array formula in cell C3:
=TEXTJOIN(«, «, TRUE, IF(COUNTIF(B3, «*»&$E$3:$E$7&»*»), $E$3:$E$7, «»))

If Cell contains A B C then how to show in One one column .

The post is helpful!

I tried the array formula to return the actual match but it didn’t work for me. I selected C3:C15, copied the formula in the comment section and pressed ctrl+shift+enter but all the cells reflected the array formula <=TEXTJOIN(«, «, TRUE, IF(COUNTIF(B3, «*»&$E$3:$E$7&»*»), $E$3:$E$7, «»))>.

May I know if I did something wrong?

Did you enter the curly brackets? If you did, don’t. They appear automatically to confirm that you successfully entered an array formula.

Thanks alot for posting this. It has really sorted me out. I will shine like a super star. I owe you tons! be blessed!

Great Help!! Oscar.. Thank you very much!!

array formula works for me perfectly well, but my file has a lot of data, around 2000 rows and excel results in hung due to lot of processing.
is there any way to make it more quicker; as this file has many formulas apart from the one that you have mentioned and that worked for me.

appreciate if you can assist further.

I want it to only return the value if it finds exact match. For example if my list contains black cat, white cat because it contains the word cat it is bringing it up.
Can you help?

I am also experiencing this issue

Thank you for article. It helped me to automate an excel file and save a lot of time! Is it possible to return all the values from a list instead of just one.

For eg: If in list A, i have ABC,DEF,GHI and in list B I have ABC and DEF. I want it to return both ABC and DEF values for list A. Right now it is only returning one value that is ABC (the first value in the list B) instead of both (ABC and DEF).

If it helps the formula I am using is

=IFERROR(INDEX(abc_l, SMALL(IF(COUNTIF($E153, «*»&abc_l&»*»), MATCH(ROW(abc_l), ROW(abc_l)), «»), COLUMNS($A$1:A152))), «»)

Thank you again for the article!

Thanks for this very useful formula. I know a lot of what Excel can do, just not how to make it do it.
I’m using the formula
=TEXTJOIN(«, «, TRUE, IF(COUNTIF(B3, «*»&$E$3:$E$7&»*»), $E$3:$E$7, «»))

Thank you so much!

I cannot see any of the «images» where you say, «the image above.» I think that would really help me to follow along.

I’ve tried multiple browsers and machines.

I am specifically looking at the formula for Previous Versions to return a match. I think seeing the example would really help me follow, as I haven’t gotten it down yet. Thank you!

=IFERROR(INDEX($G$3:$G$7, SMALL(IF(COUNTIF($B3, «*»&$G$3:$G$7&»*»), MATCH(ROW($G$3:$G$7), ROW($G$3:$G$7)), «»), COLUMNS($A$1:A1))), «»)

Thanks so much for this but I’ve gotten into knots trying to modify a working formula
=IFERROR(INDEX(OfferDetails[#Data],SMALL(IF(OfferDetails[OC ‘#]=rngOC,ROW(OfferDetails[#Data])-ROW(OfferDetails[#Headers])), ROW(2:2)), MATCH($C$14, OfferDetails[#Headers], 0)),»»)
with
=IFERROR(INDEX(OfferDetails[#Data],SMALL(IF(OR(COUNTIF(OfferDetails[OC ‘#],»*»&rngOC&»*»))=rngOC,ROW(OfferDetails[#Data])-ROW(OfferDetails[#Headers])), ROW(1:1)), MATCH($C$14, OfferDetails[#Headers], 0)),»»)

My column OfferDetails[OC ‘#] earlier had just one record example — 685-cf-18A . Now it has three 685-cf-18A ,685-cf-24b, 685-cf-11c .
I need to be able to match one of these three to rngOC.

Simply cannot figure out what is going wrong . Any suggestions I could try please ?
Anandi

I have this formula in a spreadsheet. It used to work, but now it does not. Are you aware of updates that would make it stop working?

where colors is a defined range of cells on another tab in the spreadsheet

Strangely, in a list of about 2000 names of which many should return a «yes», I get exactly one «yes», and I can’t figure out what’s special about that one. For example, the word that hits isn’t the first one in the list of things I’m looking for or anything like that.

Seems worth noting that using the SEARCH formula, I am able to get the names that I would expect to hit against my list to do so. For example, for «White-tailed eagle», Excel agrees that the word «white» is in the cell, if I check only against the cell that has «white» in it. It’s just a problem of searching against a list.

This was super helpful and works for me at identifying key words in a list of book titles. Is there a way to search multiple fields at once? (e.g., Find any word (from the array) in cells B3, L3, or Q3)

Thank you. This is very helpful. I was wondering if there was a way to display one specific word when a word from a list is found?
For example,
I have 5 lists (A,B,C,D,E) and in each list there are a set of specific words unique to just that list. How could I have it check each cell and display the List Name when the cell contains a word from that list?
In my situation there will «not» be multiple words in the search cell that are in the lists. Each cell will only contain one word from the 5 lists. Thanks for your time!

Formula in cell I3:

Hello .. I am looking for this answer as well .. is there a operator that could make it so that only an exact match of the row is returned? similar to this question

I want it to only return the value if it finds exact match. For example if my list contains black- cat, white-cat because it contains the word cat it is bringing it up.
Can you help?

I am curious of the same thing. I am currently using the formula above but need to have an exact match instead of a partial word match. Any help on this?

Thanks for your post! I am not an Office 365 subscriber and I have attempted the version of the formula that doesn’t use the TEXTJOIN function but it isn’t working, and I entered the formula as an array formula.
[IFERROR(INDEX($G$2:$G$60, SMALL(IF(COUNTIF($B2, «*»&$G$2:$G$60&»*»), MATCH(ROW($G$2:$G$60), ROW($G$2:$G$60)), «»), COLUMNS($A$1:A1))), «»)]

Upon digging, I discovered that it isn’t working because this portion of the formula COUNTIF($B2, «*»&$G$2:$G$60&»*»)is returning only the value of the first cell in my range. I’m unsure of what I’m doing wrong, and I have checked multiple times to ensure I have entered the formula as an array. Using Excel 2016. Please do you have any recommendations? Thank you!

the array formula returns one value per cell, did you copy the cell and paste to adjacent cells to the right as well?

I’ve used the formula =INDEX($E$3:$E$7, MATCH(1, COUNTIF(B3, «*»&$E$3:$E$7&»*»), 0))
However, it searches from left to right.
For examples: in cell B3 value is «MVN, YNO, XBF»
after applying the formula (=INDEX($E$3:$E$7, MATCH(1, COUNTIF(B3, «*»&$E$3:$E$7&»*»), 0))) I am getting result as «MVN».

I want the last value (that mean it should search from right instead of left).

The reason to get this type of result is there are multiple agents in particular conversation, and I in my cell value the latest agents will be at last and that is what I want).

Here is the screen shot

try this:
=INDEX($E$3:$E$7, MATCH(2, COUNTIF(B3, «*»&$E$3:$E$7&»*»), 1))

Nope it is not working.

please disregard this. Let me check again.

I’ve checked it is not working, it is only working when there are only 2 or 3 values in the cell, ,, if there are multiple for examples 5 or 6 it is not working.

It seems to be working here, can you post a screenshot when it is not working?

I’ve tried it is not working. It is just working for the first cell after that if you drag it down it doesn’t work.

here is the google link where I’ve uploaded excel file, please have a look.

you are right. It doesn’t work.
Try this array formula:
=INDEX($E$3:$E$7, MATCH(2, 1/COUNTIF(B3, «*»&$E$3:$E$7&»*»)))

It’s working. Thank you very much.

You won’t believe I was working on this from a long time and somehow I landed on this website where finally it is fixed. By the way, I have to most of my work on excel to prepare reports, work on raw data and compile files, so your formulas and other stuff helped me a lot.

Hi! This formula sorted my issue out!
=INDEX($E$3:$E$7, MATCH(1, COUNTIF(B3, «*»&$E$3:$E$7&»*»), 0))

Thank you so much! I spent countless hours trying to figure this out. you are a lifesaver!!

If a cell contains a value from a list I want it to return a value from an adjacent list
If anyone can help, I’d really appreciate it.

Seems the above formulas are very close to it but I can’t seem to get it to work

I need help in similar lines. I have a text that will be a part of a array, There will be other text as well in that cell that has this text in the array, I want to find that text in the array and return the values in that cell

How it work with cell D3 in last case, when we just take small value from array for index function?
it’s mean how take next value in array if have more values match.

Please give me your idea/advice.
Thank you very much.

I tried this and it didn’t work for me. All the results show as zeroes. And yes, I did the CTRL-SHIFT-ENTER to add the braces with no change. I am using Excel 2016.

Make sure you check the cell references, and that you enter the formula in one cell and then copy the cell and paste to cells below.

I have about 2 thousand records to check and list as long as 155 values in a column. So, I modified and tried this but it didn’t work for me. All the results show as zeroes. And yes, I did the CTRL-SHIFT-ENTER to add the braces with no change. I am using Excel 2016.

All the results show as zeroes.
Your result is weird, the IF function returns either «Yes» or nothing «», not zeros. Use the «Evaluate Formula» tool to see what is wrong.

Cell reference B3 points to the first cell in your list of about 2000 records.

$E$3:$E$7 references your list containing 155 values. Make sure you use $ to make the cell references absolute (locked).

Hi Oscar, GREAT work!

I got your «2. Display matches if the cell contains text from a list» working nicely in Excel 365 (textjoin is functional).

Thing is, what I REALLY need is to list all those values that are NOT in the reference LIST. I tried using the boolean NOT, but I can’t make it work.

In your example above, I would need:

Description Category List
————- ————- ——
ZDS, YNO, XBF YNO MVN
CAU, ZDS, XXS CAU, XXS QLL
NQM, BJC, UND NQM, BJC, UND BQX
BQX, USE, HGO USE, NGO ZDS
MXH, YGO, EZO MXH, YGO, EZO XBF

I tried brute force: first getting the existing values in one cell (as you show) and then trying to extract the differing values, but couldn’t.

Could you illuminate me on what the elegant process be for this need?

btw: I had the same issue as others commented here. I was getting a hit for both «act» and «actually» when I only wanted «act». I solved it via brute force, changing both the items and the list into «[act]» and [actually] so the search was exact. It’s working, so don’t worry about this.

Great question, I have added another section to this article that I think answers your question: Filter delimited values not in list (Excel 365)

I’ll look at your new article and comment ASAP

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